Momentum = Mass × Velocity
According to this formula,
Momentum of deer = 176 × 19 = 3344 kg•m/s.
Since you are heading north and the deer is running towards you, the direction of the deer' s momentum is north as well.
Answer:
(a) 81.54 N
(b) 570.75 J
(c) - 570.75 J
(d) 0 J, 0 J
(e) 0 J
Explanation:
mass of crate, m = 32 kg
distance, s = 7 m
coefficient of friction = 0.26
(a) As it is moving with constant velocity so the force applied is equal to the friction force.
F = 0.26 x m x g = 0.26 x 32 x 9.8 = 81.54 N
(b) The work done on the crate
W = F x s = 81.54 x 7 = 570.75 J
(c) Work done by the friction
W' = - W = - 570.75 J
(d) Work done by the normal force
W'' = m g cos 90 = 0 J
Work done by the gravity
Wg = m g cos 90 = 0 J
(e) The total work done is
Wnet = W + W' + W'' + Wg = 570.75 - 570.75 + 0 = 0 J
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
![a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}](https://tex.z-dn.net/?f=a%27%3D%20%5Cfrac%7B2F%7D%7B%20%5Cfrac%7Bm%7D%7B2%7D%20%7D%20%3D%20%5Cfrac%7B4F%7D%7Bm%7D%20%3D%204%5Cfrac%7BF%7D%7Bm%7D%20)
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
A step-down transformer has more loops in : A. Primary coil
Primary coil refers to the coil to which alternating voltage is supplied. It's usually connected to the AC supply
hope this helps
Explanation:
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