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ludmilkaskok [199]
3 years ago
13

9.6 dm= _____ cm

Mathematics
2 answers:
Sergio039 [100]3 years ago
8 0

Answer:

96 cm

53 cm

4,5 Cm

1,5 Cm

1.7dm

0,5m

Step-by-step explanation:

Dm to Cm ×10

mm to cm ÷10

Sever21 [200]3 years ago
5 0
93 cm
53 cm
4,5 cm
1,5 cm
1.7 dm
0,5 m




Hope this helped :)
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Sedaia [141]
Ok I’ll break this down so it’s easier to understand:

So you start of with $80

The first step is to find 20% off

An easy way to find 20% is to divide it by 5.

80/5= 16

And since it’s 20% OFF we subtract 16 from 80

80-16= 64

Next we need to do the coupon

It is $5 off so

64-5= 59

And finally the rebate which is $2

59-2= 57

Answer:
57
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3 years ago
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Does this equation support the Law of Conservation of Mass? Why or why not? *
Olenka [21]

Answer:

No, because the equation has to be balanced, I dont know if you meant to write 2 Co2 on the product side, but either way, it isnt balanced.

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3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

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3 years ago
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Kisachek [45]

The same as last time

Step-by-step explanation:

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Please explain your answer!
Helga [31]
Y = x^2 + 6 doesn’t not belong in the group.

When graphing an x squared it will appear as an parabola (an U shaped graph).

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