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Ksju [112]
3 years ago
14

Can someone help me solve this problem for me!!!!!! I need help on this ASAP!!!!!!! Now

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
The inverse is simply f(x)^-1 = 6/5x-2.
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Use synthetic division to find the quotient and remainder. Express your answer as a polynomial.
OLEGan [10]

1. 2x³ - 11x² + 13x - 21   ÷   x - 3

x - 3 = 0   ⇒ x = 3

3   |   2   -11   13   -21

    <u>|   ↓    6   -15    -6</u>

        2   -5    -2    -27

1. Answer: 2x² - 5x - 2 - \frac{27}{x - 3}

*************************************************************

2. 3x³ + 7x² - 13x + 10   ÷   x + 2

x + 2 = 0   ⇒   x = -2

-2  |   3    7   -13    10

    <u>|   ↓   -6    -2    30</u>

        3    1    -15    40

2. Answer: 3x² + x - 15 + \frac{40}{x + 2}

3. 2x³ + 13x² - 21x + 9   ÷   x - 1

x - 1 = 0   ⇒   x = 1

1  |   2    13   -21     9

    <u>|   ↓     2    15    -6</u>

        2    15    -6    3

3. Answer: 2x² + 15x - 6 + \frac{3}{x - 1}

4. 7x³ + 0x² - 8x + 16   ÷   x - 2

x - 2 = 0   ⇒   x = 2

2  |   7    0     -8     16

    <u>|   ↓    14    28    40</u>

        7    14    20    56

4. Answer: 7x² + 14x + 20 + \frac{56}{x - 2}

5. 8x⁴ - 14x³ - 71x² - 10x + 24   ÷   x - 4

x - 4 = 0   ⇒   x = 4

4  |   8   -14   -71    -10    24

    <u>|   ↓    32    72     4   -24 </u>

        8    18       1     -6     0

5. Answer: 8x³ + 18x² + x - 6


8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="absmiddle" class="late
olga55 [171]
Answer is 25 x 2x + 729/25

6 0
3 years ago
5x-3y-z<br> If x= -2, y=2 and z= -3
Mademuasel [1]
This is fairly simple
Plug in the numerical values given for each variable.
5(-2) -3(2) -(-3)
-10 -6 + 3 (negative x negative = positive)
-16 + 3
-13 is the final answer
6 0
3 years ago
Elijah and his sister went to the movies. They had $34 altogether and spent $9.50 per ticket. Elijah and his sister bought the s
mestny [16]
The spent 4.50 individual and 9.50 together and they have 24.50
8 0
3 years ago
Which expressions are equivalent to \dfrac{2^5}{6^5}
DerKrebs [107]

We have been given an expression \frac{2^5}{6^5}. We are asked to choose the expressions, which are equivalent to our given expression.

Using exponent property \frac{1}{a^n}=a^{-n}, we can rewrite our given expression as:

\frac{2^5}{6^5}=2^5\cdot 6^{-5}

Upon looking at our given choices, we can see that option D is the correct choice.

Let us simplify our given expression.

\frac{2^5}{6^5}=\frac{2^5}{(2\cdot 3)^5}

\frac{2^5}{6^5}=\frac{2^5}{2^5\cdot 3^5}

Upon cancelling out 2^5 from numerator and denominator, we will get:

\frac{2^5}{6^5}=\frac{1}{3^5}

Using exponent property \frac{1}{a^n}=a^{-n}, we will get:

\frac{1}{3^5}=3^{-5}

Therefore, option B is a correct choice as well.

3 0
4 years ago
Read 2 more answers
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