Greater than (less space = less room for the particles to bounce around in = bounce around faster (hits walls/each other more often) = greater pressure)
<span>BaCl2+Na2SO4---->BaSO4+2NaCl
There is 1.0g of BaCl2 and 1.0g of Na2SO4, which is the limiting reagent?
"First convert grams into moles"
1.0g BaCl2 * (1 mol BaCl2 / 208.2g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2 ) = 1.5 mol Na2SO4 / mol BaCl2
"From this ratio compare it to the equation, BaCl2+Na2SO4---->BaSO4+2NaCl"
The equation shows that for every mol of BaCl2 requires 1 mol of Na2SO4. But we found that there is 1.5 mol of Na2SO4 per mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
Answer:
Molarity = 0.5 M
Explanation:
Given data:
Mass of NaCl = 2.7 g
Volume = 100 mL(100×10⁻³L)
Molarity of solution = ?
Solution:
Formula:
Molarity = number of moles / volume in litter
Number of moles:
Number of moles = mass/ molar mass
Number of moles = 2.7 g/ 58.5 g/mol
Number of moles = 0.05 mol
Molarity = number of moles / volume in litte
Molarity = 0.05 mol / 100×10⁻³L
Molarity = 0.5 M
