X^2-12x+7=0 move constant to other side
x^2-12x=-7 add the square of half the linear coefficient to both sides...(12/2)^2=36
x^2-12x+36=29 now the left side is a perfect square...
(x-6)^2=29 so if
f(x)=(x-a)^2+b then
f(x)=(x-6)^2-29
So a=6
Answer:
(x - 5)² - 25
Step-by-step explanation:
Using the method of completing the square
add/ subtract ( half the coefficient of the x- term)² to x² - 10x
x² + 2(- 5)x + 25 - 25
= (x - 5)² - 25
Step-by-step explanation:
By solving, I am assuming that you want to find the zeros.
So to find what x equals, first, you factor out an x.
3x² - 4x = 0
x(3x - 4) = 0
Here, you can separate the equation into two different equations to solve for x.
- <em>3x - 4 = 0</em> and <em>x = 0</em>
- x =
and x = 0
Those are your zeros.
And for its graph, you can always look to an online graphing calculator. I used Desmos.
Answer:
1/20
Step-by-step explanation:
1/20 +x = ⅒
multiply through by 20
1+20x=2
1-2=-20x
-1= -20x
1/20=x