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3 years ago

An ocean current moving from the equator toward a pole is

Physics

2 answers:

kobusy [5.1K]3 years ago

8 0

Answer:

A warm current is moving away from the equator towards the poles. The water in a warm current is warmer than the surrounding water.

Viefleur [7K]3 years ago

3 0

Answer:

A warm current

Explanation:

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A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.

mixas84 [53]

P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s

8 0

2 years ago

Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot

alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold $T_{1} = 78$ K

Temperature of gas when it is hot $T_{2} = 300$ K

The efficiency of a stirling engine,

$\eta =1 - \frac{T_{1} }{T_{2} }$

$\eta = 1- \frac{78}{300}$

$\eta = 1-0.26$

$\eta = 0.74$

∴ $\eta = 74 \%$

Therefore, the efficiency of a Stirling engine is 74%

5 0

3 years ago

Hardness and density are physical properties.<br> a. True<br> b. False

antiseptic1488 [7]

a . true hardness and density are physical properties

7 0

3 years ago

Read 2 more answers

A wave has a frequency of 5 HZ and a speed of 25 m/s. what is the wavelength of a wave?

svp [43]

Wave speed = frequency * wavelength

We need to rearrange this equation because we are finding the wavelength :

Wavelength = wave speed / frequency

To rearrange it, I just divided it by frequency so that wavelength was the subject.

Now, input these numbers into this equation :
Wavelength = wave speed / frequency
Wavelength = 25 / 5
Wavelength = 5m

5 0

3 years ago

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Determine the magnitude of the electric field at the point P. Express your answer in terms of Q, x, a, and k. Express your answe

Sav [38]

Complete Question

The question image is in the first uploaded image

Answer:

$E=\frac{KQ*4xa}{(x^2-a^2)^2}$