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KiRa [710]
3 years ago
11

Sb-6 white lights can sometimes be found on what kind of buoys

Physics
1 answer:
Hitman42 [59]3 years ago
4 0

<span>The white lights can sometimes be found on the kind of buoys called the mid channel buoys or mid channel mark, they are the ones who provides information to sailors or it serves as an indication the presence of a deep water channel.</span>

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What is a good hypothesis when putting pop rocks into soda?
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That it will erupt upon contact. Hope it helps!
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3 years ago
What type of circuit is in the diagram? Group of answer choices:
eduard

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Series circuit

Explanation:

Because the electrical components are connected one after each other in a single loop, rather than alongside each other, forming extra loops.

8 0
3 years ago
Read 2 more answers
A block is at rest on the incline shown in the figure. The coefficients of static and ki- netic friction are μs = 0.62 and μk =
GREYUIT [131]

The frictional force is 218.6 N

Explanation:

The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.

There are two forces acting along this direction:

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mg sin \theta

where

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g=9.8 m/s^2 is the acceleration of gravity

\theta=29^{\circ} is the angle of the incline

- The (static) frictional force, acting upward, of magnitude F_f

Since the block is in equilibrium, we can write

mg sin \theta - F_f = 0

And substituting, we find the force of friction:

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Learn more about frictional force along an inclined plane:

brainly.com/question/5884009

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7 0
3 years ago
A car has an initial velocity of 9 km/hr and a final velocity of 66 km/hr. What is the cars average velocity? Use one of the fol
Karolina [17]

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7 0
3 years ago
What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27
gayaneshka [121]

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

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λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

8 0
4 years ago
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