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2 years ago

There is a repulsive force between two charged objects when ____________ .

1 answer:

3 0

There is a repulsive force between two charged objects when they are of like charges/ they are likely charged (like charges repel each other)

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If the earth's magnetic field has strength 0.50 gauss and makes an angle of 20.0 degrees with the garage floor, calculate the ch

lys-0071 [83]

Answer:

ΔΦ = -3.39*10^-6

Explanation:

Given:-

- The given magnetic field strength B = 0.50 gauss

- The angle between earth magnetic field and garage floor ∅ = 20 °

- The loop is rotated by 90 degree.

- The radius of the coil r = 19 cm

Find:

calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.

Solution:

- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.

- The strength of magnetic field B and the are of the loop A remains constant. So we have:

Φ = B*A*cos(θ)

ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )

- The initial angle θ_1 between the normal to the coil and B was:

θ_1 = 90° - ∅

θ_1 = 90° - 20° = 70°

The angle θ_2 after rotation between the normal to the coil and B was:

θ_2 = ∅

θ_2 = 20°

- Hence, the change in flux can be calculated:

ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )

ΔΦ = -3.39*10^-6

8 0

3 years ago

Two light bulbs are being used in a lab experiment with a single battery. Bulb A has half the resistance as Bulb B. Which bulb i

Naya [18.7K]

Answer and Explanation:

It is given that bulb A has the half the resistance as B

WHEN THEY ARE CONNECTED IN SERIES : In series circuit we know that current is same in the whole circuit

The power is given by $P=i^2R$ the expression it is clear that the bulb which has more resistance consume more power as current is same, and the bulb which consume more power will be brightest

It is given that resistance of bulb A is half the resistance of B So bulb A will be dimmest in this case

WHEN THEY ARE CONNECTED IN PARALLEL : In parallel circuit voltage is same across the circuit

The power is given by $P=\frac{V^2}{R}$ from the expression it is clear that the bulb which has least resistance will consume more power and so will be brightest

As the resistance of bulb A is less so it will be brightest in this case

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3 years ago

Atoms form chemical bonds using:

yan [13]

A electrons in the innermost energy level

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2 years ago

Which atomic particle gives an atom gives it it’s chemical properties? Question 3 options: A.Isotopes B.Neutrons C.Electrons D.P

bulgar [2K]

C. is your answer! Hope it helps!

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3 years ago

Read 2 more answers

A hollow metal sphere has a 5 cm inner radius and a 12 cm outer radius. There is a particle at the center of the sphere. The sur

Gelneren [198K]

Answer:

Explanation:

The surface charge density on the inside surface of the sphere is -150nC/m2

Charge on the inner surface = - 4 π x (.05)² x 150 x 10⁻⁹

= - 4.71 x 10⁻⁹ C

This is the bound charge . This charge will be bound by charge at the centre

equal to the same charge but of opposite nature .

So charge at the centre

Q = + 4.71 x 10⁻⁹ C

B) Imagine a Gaussian surface with radius equal to 4 cm

If E be electric field on the surface

Flux through the surface

4 π x (.04)² x E = Q / ε₀

= 4.71 x10⁻⁹ / 8.85 x 10⁻¹²

= .532 x 10³

E = .532 x 10³ / 4 π x (.04)²

= 26473 N/C

C )Imagine a Gaussian surface with radius equal to 8 cm

If E be electric field on the surface

Flux through the surface

4 π x (.08)² x E = Q / ε₀

= 0 / 8.85 x 10⁻¹² ( Total charge inside will be -Q + Q = 0 )

= 0

Total charge on the outer surface

= 4 π x (.12)² x 150 x 10⁻⁹

= 27.13 x 10⁻⁹ C

Imagine a Gaussian surface with radius equal to 20 cm

If E be electric field on the surface

Flux through the surface

4 π x (.12)² x E = Q / ε₀

= 27.13 x10⁻⁹ / 8.85 x 10⁻¹² ( - Q + Q will cancel each other )

= 3.065 x 10³

E = 3.065 x 10³ / 4 π x (.12)²

= 16946.43 N/C

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2 years ago