1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka [77]
2 years ago
7

There is a repulsive force between two charged objects when ____________ .

Physics
1 answer:
xxTIMURxx [149]2 years ago
3 0
There is a repulsive force between two charged objects when they are of like charges/ they are likely charged (like charges repel each other)
You might be interested in
I need help with this
mel-nik [20]
It’s 4. Definitely 4. 99% sure it’s 4.
4 0
2 years ago
A jet on an aircraft carrier can be launched from rest to 40 m/s in 2 seconds. What is the acceleration of the aircraft? Show st
Alex_Xolod [135]

Answer:

a=20\ m/s^2

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 40 m/s

Time, t = 2 s

We need to find the acceleration of the aircraft. We know that, acceleration is equal to the rate of change of velocity. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{40-0}{2}\\\\=20\ m/s^2

So, the acceleration of the aircraft is 20\ m/s^2.

5 0
2 years ago
Is hydrogen energy renwable? Why<br> How is it used nowadays<br> How is it obtained?
hram777 [196]

Answer:

t

Explanation:

5 0
2 years ago
Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
3 years ago
A 1980-kg car is traveling with a speed of 15.5 m/s. What is the magnitude of the horizontal net force that is required to bring
Dennis_Churaev [7]

Answer: 6067.5 N

Explanation:

Work = Change in Energy. To start, all of the energy is kinetic energy, so find the total KE using: KE = 1/2(m)(v^2). Plug in 1980 kg for m and 15.5 m/s for v and get KE = 237847.5 J.

Now, plug this in for work: Work = Force * Distance; so, divide work by distance to get 6067.5 N.

5 0
2 years ago
Other questions:
  • Which of the following statements are true of solids? A.The particles do not vibrate. B.The particles are in a fixed location. C
    6·1 answer
  • Ask Your Teacher When a potential difference of 160 V is applied to the plates of a parallel-plate capacitor, the plates carry a
    10·1 answer
  • The motor of a four wheeler traveling along a muddy trail generates an average power of 7.05 104 W when moving at a constant spe
    14·1 answer
  • Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one’s birth. The on
    5·1 answer
  • Question 6 of 25
    5·2 answers
  • How does the law of conservation of mass apply to this reaction:Al+3HCl--&gt;H2+AlCl3
    9·1 answer
  • Is average speed a scalar or vector quantity? why?
    6·1 answer
  • When a charged particle moves along a helical path in a uniform magnetic field, which component determines the pitch of the path
    10·1 answer
  • Data chart: (5 pts)
    10·1 answer
  • A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!