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3 years ago

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Two boats are anchored in the harbor, separated by a horizontal distance of 18 m. The boats bob up and down as waves enter the h

arbor. When one boat is at its highest point, the other is at its lowest point and there is one wave crests between them. Each boat makes exactly 2 complete up-and-down cycles every 16.0 s. The vertical distance between a boat's highest and lowest position is 3.6 m.

1 answer:

sineoko [7]3 years ago

4 0

<h2><u>Given</u>:</h2>

Horizontal distance between two boats = x = 14 m

One boat is at trough, the other is at crest.

As there is no crests between them meaning the boat are next to each other.

Wavelength is the distance between two consecutive crests/troughs = w

The distance between a crest and a trough next to it = w/2

Complete cycles = c = 5

Time taken for c cycles = t = 15 s

Vertical distance between two boats = y = 2.4 m

<h2><u>To find</u>:</h2>

wavelength = w = 2x = 28 m

Amplitude = A = Displacement from mean to extreme position = y/2 = 1.2 m

Time period for one cycle = T = t/c = 15/5 = 3 s/cycle

frequency = 1/T = 1/3 = 0.33 hertz

speed = wavelength/Period = w/T = 28/3 = 9.33 m/s

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<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: The \: current \: in \: a \: circuit \: is \: 5 \: amps. \: and \: resistance \: is \: 30 \: Ohms.$

$\\$

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$\\$

$\huge\bf{ \underline{ Solution:- }}$

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