All categories

3 years ago

Other than temperature, which property also has an effect on the rates of chemical reactions?

1 answer:

8 0

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B

The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.

There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.

The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.

Other factors affecting the rate of chemical reaction are:

the physical state of the reactants
surface area
temperature
and the presence of a catalyst

Therefore, the correct answer is option B

Learn more about chemical reaction here: brainly.com/question/11231920?source=archive

You might be interested in

How do I do this question?

iren2701 [21]

You take 10.0/12.0 and you will get your answer

3 0

3 years ago

Read 2 more answers

Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. what is the period

Mariana [72]

The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

Time taken to swing from leftmost point to rightmost point; $t = 1.2s$

Period of the pendulum; $T = \ ?$

<h3>What is Period?</h3>

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum $1.2s$ to swing from leftmost point to rightmost point, it will also take the pendulum $1.2s$ to swing back to its original position( leftmost point )

Hence,

$T$ = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

$T = 1.2s + 1.2s\\\\T = 2.4s$

Therefore, the time period of the simple pendulum is 2.4 seconds.

Learn more about Time Period: brainly.com/question/27135322

7 0

3 years ago

What is the concentration of H+ ions at a pH = 8?

skelet666 [1.2K]

Taking into account the definition of pH and pOH, the concentration of H⁺ ions at pH=8 is 1×10⁻⁸ M and the concentration of OH⁻ ions at pH=8 is 1×10⁻⁶ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3 /><h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of H⁺ ions</h3>

In this case, pH=8. Replacing in the definition of pH:

8= - log [H⁺]

Solving:

Finally, the concentration of H⁺ ions at pH=8 is 1×10⁻⁸ M.

<h3>Concentration of OH⁻ ions</h3>

Being pH= 8, pOH is calculated as:

pOH + 8= 14

pOH= 14 - 8

pOH= 6

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 6

Solving

Finally, the concentration of OH⁻ ions at pH=8 is 1×10⁻⁶ M.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

#SPJ1

7 0

2 years ago

How many elements did mendeleev place in group 2

Pepsi [2]

Answer:5

Explanation:

8 0

3 years ago

A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi

vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

$V=\frac {C_2V_2-C_1V_1}{C_1+C_2}$

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

$C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}$

Therefore

$V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437$

Charge, Q is given by CV hence for the first capacitor charge will be $Q_1=C_1V$

Here, $Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C$

8 0

3 years ago