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3 years ago

Volcano has both useful and harmful effects give reason

Physics

2 answers:

Mama L [17]3 years ago

6 0

Answer:

useful effects of volcano are :-

it makes soil fertile
it provides valuable nutrients for the soil

harmful effects of volcano are:-

it makes air polluted
it destroy the environment .

hope it is helpful to you ☺️

alina1380 [7]3 years ago

3 0

Answer:

harmful effects

1. that will cause air pollution

2. that will destroy our earth

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A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow

trapecia [35]

Answer:N=13.53 rpm

Explanation:

Given

radius $r=7.80 m$

Centripetal acceleration $a_c=1.6 g$

and centripetal acceleration $a_c=\omega ^2r$

where $\omega =angular\ velocity$

$1.6\times 9.8=\omega ^2\times 7.8$

$\omega ^2=2.0102$

$\omega =1.417 rad/s$

and $\omega =\frac{2\pi \cdot N}{60}$

$1.417\times 60=2\pi \cdot N$

$N=13.53 rpm$

8 0

3 years ago

The maximum potential energy of a spring system (mass 15 kg, spring constant 850 N/m) is 6.5 J. a) What is the amplitude of the

Bumek [7]

Answer:

a) 0.124 m

b) 0.93 ms⁻¹

c) 0.5 k A² cos ² ( ωt )

Explanation:

1) Potential energy = U = 0.5 k A² , where A is the amplitude and k = 850 N/m is the spring constant.

0.5 ( 850) (A² ) = 6.5

⇒ A = 0.124 m = Amplitude.

b) From energy conservation, 0.5 m v² = 6.5

⇒ speed = v = 0.93 ms⁻¹

c) If x = A cos ωt ,

Potential energy = 0.5 k A² = 0.5 k A² cos ² ( ωt )

8 0

3 years ago

a girl standing on a bridge throws a stone vertically upwards at 6 ms⁻1. it hits the water below the bridge after 2 seconds. fin

balu736 [363]

The speed at which the stone hits the water is 13.6m/s and the initial height of the stone is 7.6m.

<h3 /><h3>Speed of stone as it hits the water</h3>

Initial velocity of stone = 6 ms⁻¹

At the maximum height, the final velocity, v = 0

Acceleration of the stone, g = 9.8 ms⁻²

Time taken to reach maximum height = t₁

Using, v = u + gt₁

t₁ = v - u/g

since the stone is travelling upwards, g = -9.8 m/s⁻²

t₁ = 0 - 6/-9.8

t₁ = 0.61 s

Time take to fall from maximum height, t = 2 - 0.61s

Time take to fall from maximum height = 1.39s

Calculating the final velocity using the formula, v = u + gt

where u = 0 m/s

v = 0 + 9.8 * 1.39

v = 13.6 m/s

<h3>Initial height of stone</h3>

Initial height of stone = Height of bridge, H

Time taken by the stone to fall down from height, H in water, t = 2s

Initial velocity of stone = 6 ms⁻¹

Acceleration of the stone, g = 9.8 ms⁻²

Height of the bridge, H = -ut + gt²/2

Initial velocity is negative since it is against gravity

H = -6 * 2 + 9.8 * 2² /2

H = 7.6m

Therefore, the speed at which the stone hits the water is 13.6m/s and the initial height of the stone is 7.6m

Learn more about velocity and height at: brainly.com/question/13665920

3 0

2 years ago

A +7.00-μC point charge is moving at a constant 8.50×106 m/s in the +y-direction, relative to a reference frame. At the instant

docker41 [41]

The points are:

(a) x = 0.500 m, y = 0, z = 0 (b) x = 0, y = 0, z = +0.500 m

Answer:

a) $B = -2.38\times10^{-5} \hat k$

b) $B = 2.38\times10^{-5} \hat i$

Explanation:

The magnetic field can be calculated as follows:

$B= \frac{\mu_o}{4\pi}\frac{q (\vec v\times \hat r)}{r^2}$

a) The velocity vector is in +y direction and the point is on x-axis

Because $\hat j \times \hat i = -\hat k$ ,

$B= \frac{\mu_o}{4\pi}\frac{q (\vec v\times \hat r)}{r^2}$

$B= 1\times 10^{-7}\times 7\times 10^{-6}\times \frac{8.50\times 10^6 \hat j\times \hat i}{0.500^2}\\B = -2.38\times10^{-5} \hat k$

b) The velocity vector is in +y direction and the point is on z-axis

Because $\hat j \times \hat k = \hat i$ ,

$B= \frac{\mu_o}{4\pi}\frac{q (\vec v\times \hat r)}{r^2}$

$B= 1\times 10^{-7}\times 7\times 10^{-6}\times \frac{8.50\times 10^6 \hat j\times \hat k}{0.500^2}\\B = 2.38\times10^{-5} \hat i$

3 0

3 years ago

A circular-motion addict of mass 83.0 kg rides a Ferris wheel around in a vertical circle of radius 13.0 m at a constant speed o

Svetllana [295]

Answer:

(A) Time period T = 6.28 SEC

(B) At highest point fore is - 575.83 N

(B) At lowest point force is 1050.97 N

Explanation:

We have given that mass m = 83 kg

Radius r = 13 m

Speed v = 6.10 m/sec

(A) Time period of the motion is given by $T=\frac{2\pi r}{v}=\frac{2\times 3.14\times 13}{6.10}=6.28sec$

(b) Net force is given by $F_{NET}=\frac{mv^2}{r}=\frac{83\times 6.10^2}{13}=237.571N$

Force due to gravity $F_{gravity}=mg=83\times 9.8=813.4N$

At highest point $F_{NORMAL}=F_{NET}-F_{GRAVITY}=237.57-813.4=-575.83$

(B) At lowest point $F_{NORMAL}=F_{NET}+F_{GRAVITY}=237.57+813.4=1050.97N$

5 0

3 years ago

Volcano has both useful and harmful effects give reason​

Volcano has both useful and harmful effects give reason