Answer:
.
Explanation:
Given that,
Capacitance, ![C=1.4\times 10^{-7}\ F](https://tex.z-dn.net/?f=C%3D1.4%5Ctimes%2010%5E%7B-7%7D%5C%20F)
Charge stored in the capacitor, ![Q=3.4\times 10^{-6}\ C](https://tex.z-dn.net/?f=Q%3D3.4%5Ctimes%2010%5E%7B-6%7D%5C%20C)
We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :
![E=\dfrac{Q^2}{2C}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BQ%5E2%7D%7B2C%7D)
Put all the values,
![E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B%283.4%5Ctimes%2010%5E%7B-6%7D%29%5E2%7D%7B2%5Ctimes%201.4%5Ctimes%2010%5E%7B-7%7D%7D%5C%5C%5C%5C%3D4.12%5Ctimes%2010%5E%7B-5%7D%5C%20J)
So, the required electric potential eenergy is equal to
.
The amplitude is equivalent to the coefficient of the sine function, so:
Amplitude = 1
The time period of a Sin(x) = 2π
The time period of Sin(4x) = 2π/4 = π/2
The period is π/2
Answer:
A. velocity has a direction .. .
with magnitude too but speed has only magnitude
m = mass of the ball at the edge of the cliff = 2 kg
h = height of the cliff from where the ball falls off = 40 m
g = acceleration due to gravity = 9.8 m/s²
gravitational potential energy of the ball at the top of the cliff is given as
PE = mgh
inserting the above values in the formula
PE = (2) (9.8) (40)
PE = 784 J
KE = kinetic energy of the ball as hits the ground.
initially at the top of cliff , the ball has no kinetic energy and only potential energy. as the ball falls down the cliff , the speed of ball increase which increases the kinetic energy and potential energy decrease by same amount as the height above the ground decrease.
using conservation of energy
kinetic energy of ball as it hits the ground = Potential energy of the ball at the top of cliff
KE = PE
KE = 784 J
Sound waves travel through the air to your eardrum