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Tatiana [17]
3 years ago
11

Answer all these questions for a TON OF POINTS

Physics
2 answers:
Sladkaya [172]3 years ago
7 0

Answer:

1). E

2). A

3). 4N

4). D

Explanation:

IgorC [24]3 years ago
3 0
1). E
2). A
3). 4N
4). D
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Name 2 different "limiting Factors" that limit the size of a population in a given ecosystem.
Scrat [10]

Answer:    food, water, habitat, and mate.

Explanation:      The common limiting factors in an ecosystem are food, water, habitat, and mate. The availability of these factors will affect the carrying capacity of an environment. As population increases, food demand increases as well

8 0
3 years ago
An example of forced convection is the movement of hot air by a fan.
zavuch27 [327]
This is true. let me know if im wrong.
4 0
3 years ago
A mother and daughter press their hands together and then push apart while ice skating. Immediately after they push away from ea
kherson [118]

Answer:

J

Explanation:

The daughter moves with greater acceleration backwards because of her weight.

7 0
2 years ago
Read 2 more answers
A high-speed flywheel in a motor is spinning at 450 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and
alexira [117]

Answer:

A) \omega_f=17.503\ rad.s^{-1}

B) t=55.6822\ s

C) \theta=1312\ rad

Explanation:

Given:

  • mass of flywheel, m=40\ kg
  • diameter of flywheel, d=0.72\ m
  • rotational speed of flywheel, N_i=450\ rpm \Rightarrow \omega_i=\frac{450\times 2\pi}{60} =15\pi\ rad.s^{-1}
  • duration for which the power is off, t_0=35\ s
  • no. of revolutions made during the power is off, \theta=180\times 2\pi=360\pi\ rad

<u>Using equation of motion:</u>

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

360\pi=15\pi\times 35+\frac{1}{2} \times \alpha\times35^2

\alpha=-0.8463\ rad.s^{-2}

Negative sign denotes deceleration.

A)

Now using the equation:

\omega_f=\omega_i+\alpha.t

\omega_f=15\pi-0.8463\times 35

\omega_f=17.503\ rad.s^{-1} is the angular velocity of the flywheel when the power comes back.

B)

Here:

\omega_f=0\ rad.s^{-1}

Now using the equation:

\omega_f=\omega_i+\alpha.t

0=15\pi-0.8463\times t

t=55.6822\ s is the time after which the flywheel stops.

C)

Using the equation of motion:

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

\theta=15\pi\times 55.68225-0.5\times 0.8463\times 55.68225^2

\theta=1312\ rad revolutions are made before stopping.

3 0
3 years ago
A machine has an efficiency of 20%. Find the input work if the output work is 140J.
Ilia_Sergeevich [38]
Ummmm I don’t know this sorry
3 0
2 years ago
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