Answer all these questions for a TON OF POINTS

If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h

raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory ( $u_x$ ) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

$u^2=u_x^2+u_y^2$

Where, $u_x\ and\ u_y$ are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

$(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1$

Now, we know that, for a projectile motion, the maximum height is given as:

$H=\frac{u_y^2}{2g}$

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

$H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m$

Therefore, the maximum height reached is 4.63 m.

3 0

4 years ago

Which of the following statement is false

just olya [345]

A, the statement is incorrect

6 0

3 years ago

A hot-air balloon is 150 ft above the ground when a motorcycle (traveling in a straight line on a horizontal road) passes dir

Katyanochek1 [597]

Answer:

dR/dt = 10.2 ft / s

Explanation:

Let's work this problem by finding the distance between the balloon and the motorcycle and then drift for the speed change of the distance

Balloon

y = y₀ + $v_{oy}$ t

Motorcycle

x = v₀ₓ t

Distance, let's use Pythagoras' theorem

R² = x² + y²

R² = (v₀ₓ t)² + (y₀ + $v_{oy}$ t)²

v₀ₓ = 88 ft / s

$v_{oy}$ = 8 ft / s

y₀ = 150 ft

R² = (8 t)² + (150 + 8 t )²

R² = 64 t² + (150 + 8t )²

This is the expression for the distance between the two bodies, the rate of change is the derivative with respect to time (d / dt)

2RdR / dt = 64 2 t + 2 (150 + 8t) 8

dR / dt = [64 t + (1200 + 64t )] / R

dR/dt = (1200 +128 t)/R

Let's calculate for the time of 10 s

dR / dt = (1200 + 128 10) / R = 2480 /R

R = √ [64 10² + (150 + 8 10)²

R = √ [6400 + 52900]

R = 243.5 ft

dR / dt = (2480) / 243.5

dR / dt = 10.2 ft / s

8 0

4 years ago

Which of the following best describes each particle?

Nana76 [90]

Answer:

C. Protons are positive, neutrons are neutral, and electrons are negative

4 0

3 years ago

On the surface of the earth, weight is calculated by:

sdas [7]

On the surface of the earth, weight is calculated by multiplying mass and gravity.

<span>Because we know the radius of the Earth, we can use the Law of Universal Gravitation to calculate the mass of the Earth in terms of the gravitational force on an object (its weight) at the Earth's surface, using the radius of the Earth as the distance. We also need the Constant of Proportionality in the Law of Universal Gravitation, G. This value was experimentally determined by Henry Cavendish in the 18th century to be the extemely small force of 6.67 x 10</span>-11 Newtons between two objects weighing one kilogram each and separated by one meter. Cavendish determined this constant by accurately measuring the horizontal force between metal spheres in an experiment sometimes referred to as "weighing the earth."

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0

4 years ago

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