m1= mass 1 = 1.1 kg
Vi1 = initial velocity 1 = 2.7 m/s
m2= 2.4 kg
V2i = -1.9 m/s
We assume east as positive and west as negative.
Apply the formulas:
Vf1 = ?
Replacing:
Answer: 3.6 m/s west
So the acceleration of gravity is 9.8 m/s so that’s how quickly it will accelerate downwards. You can use a kinematic equation to determine your answer. We know that initial velocity was 19 m/s, final velocity must be 0 m/s because it’s at the very top, and the acceleration is -9.8 m/s. You can then use this equation:
Vf^2=Vo^2+2ax
Plugging in values:
361=19.6x
X=18 m
X Represents the distance the spring is stretched or compressed away from its equilibrium or rest position.
Answer:
Explanation:
given data:
density of water \rho = 1 gm/cm^3 = 1000 kg/m^3
height of water = 20 cm =0.2 m
Pressure p = 1.01300*10^5 Pa
pressure at bottom
= 1.01300*10^5 - 1000*0.2*9.8
= 99340 Pa
h_[fluid} = 0.307m
if in 1 second the jet goes 428 meters and you want to know how long it takes to go 237 meters you just divide 237/428
it can be written like this
_1_ = __x__
428 237
cross multiply
428 times x = 1 times 237
428x=237
divide by 428 on both sides
x= 237/428
x=0.5537 seconds
