. A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an
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Answer:
The angle above the horizontal at which the pitcher throws the ball determines the distance the ball travels before returning to the height at which it was thrown
Explanation:
The baseball is thrown as a projectile and the range, 'R', of the baseball which is the distance the baseball travels before the height above the ground returns to the initial height is given given as follows;
Where;
R = The range of the baseball = The horizontal distance away from the pitcher the ball reaches
u = The initial velocity with which the baseball was thrown
θ = The angle above horizontal a baseball pitcher throws the ball
g = The acceleration due to gravity ≈ 9.81 m/s²
From the the equation, when θ = 0, sin(θ) = sin(0) = 0 and the ball does not cover any horizontal distance before going lower than the height at which it was thrown, therefore, for the ball to travel further, the angle of launch, θ has to be larger than 0.
The vertical velocity of the ball is: 
. Since gravity acts at 
, this means that the time of flight up to the maximum height (at which vertical velocity is 0) would be:
This maximum height is:
Then the time for it to fall down will be:
The total time will be 3.69 + 3.73 = 7.42 seconds.
This maximum height is:
Then the time for it to fall down will be:
The total time will be 3.69 + 3.73 = 7.42 seconds.