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3 years ago

When is the power to power rule used?

Mathematics

1 answer:

arsen [322]3 years ago

5 0

Answer:

The "power rule" tells us that to raise a power to a power, just multiply the exponents.

Step-by-step explanation:

math

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A cone with diameter 20 yd and a height of 20<br> yd.

stich3 [128]

What would you like to know? The total surface area? The lateral surface area? The volume, perhaps? The radius?

5 0

3 years ago

-X² + 5x - 6 = 2<br> Using the quadratic formula

Ivenika [448]

$-x^2+5x-6=2\\-x^2+5x-6-2=0\\-x^2+5x-8=0\\$

↝ Form into $ax^2+bx+c = 0$ where a > 0 (Optional)

$x^2-5x+8=0$ ↝ Multiply -1 for both sides.

↝ Then proceed with the Quadratic Formula.

x = [-b ± (√b²-4ac)]/2a ↝ Quadratic Formula

$x=\frac{-(-5)+-\sqrt{(-5)^2-4(1)(8)}}{2(1)}\\x=\frac{5+-\sqrt{25-32}}{2}\\$

↝ As you can see that inside the square root, the numbers cannot be negative. Therefore, the solutions are imaginary.

↝ Solution with Real Numbers System ↝ There are no real solutions.

↝ Solution with Complex Number System ↝

$x=\frac{5+-\sqrt{25-32}}{2}\\x=\frac{5+-\sqrt{-7}}{2}\\x=\frac{5+-\sqrt{7}i }{2}$

Therefore, the answer for Complex Number System is (5±√7i)/2

3 0

3 years ago

Complete for y=x-4. How do I do this pls help

Hitman42 [59]

Answer:

-5 = -9

-2 = -6

0 = -4

4 = 0

Step-by-step explanation:

You substitute each value for x and then solve the equation. (Please give me brainliest)

8 0

3 years ago

: Kevin is planting 15 bushes and 9 trees in rows. If he wants all the rows to be exactly the same, with no plants left over, wh

Flauer [41]

Answer:

The greatest number of rows that can be planted, and have nothing left over, would be 3

Step-by-step explanation:

Find the greatest common factor (gcf) of 15 and 9

15: 1 3 5 15

9: 1 3 9

In this case, the gcf of 15 and 9 would be 3.

5 0

3 years ago

Read 2 more answers

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

7 0

3 years ago