Answer:
(2⁵)²: 1024 combinations
Explanation:
In this case, the chromosome haploid number (n) of the target species is equal to 10, and therefore its diploid number (2n) is equal to 5 (i.e., somatic cells in the target species contain 5 pairs of chromosomes). That means that one individual can produce 2⁵ or 32 different gametic combinations. Moreover, the number of possible combinations that emerge from paring different gametes (sexual reproduction) can be calculated as (32)² = 1024 combinations.
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
One electron is transferred in the ionic bond because sodium needs to lose one electron and chlorine needs to gain one electron to have a full energy shell, which is the ultimate goal in any bond.
Brainliest please :)
Answer:
The density would stay the same.
Explanation:
The density would stay the same as density is an intensive property meaning it doesn't change based on the amount of matter that you have.
