Explanation:
When OH- (as in potassium hydroxide) is added, it reacts with the acid (HOCl) to reduce the amount of HOCl and increase the concentration of sodium hypochlorite.
Potassium hydroxide will react with the hypochlorous acid to produce hypochlorite ions. In the process, some of the weak acid will be consumed, along with the added strong base.
This occurs as follows:
HClO(aq) + KOH(aq) → KClO(aq) + H2O(l)
since water is formed, this maintains the pH. Thus ...
A. The number of moles of HClO will decrease. - TRUE
B. The number of moles of ClO- will increase. - TRUE
C. The equilibrium concentration of H3O+ will remain the same. - TRUE
D. The pH will decrease. - FALSE
E. The ratio of [HClO] / [ClO-] will decrease. -TRUE. It will decrease as HClO goes down and ClO- goes up.
Answer:
Hematology is the study of blood
Explanation:
The cellular component consists of three major cell types, all of which arise from hematopoietic stem cells located primarily in the bone marrow: red blood cells (RBCs), white blood cells (WBCs), and platelets.
Answer:
1 x 10⁻¹¹ M
Explanation:
<u>(Step 1)</u>
Determine the pH.
pH = -log[H⁺]
pH = -log[1 x 10⁻³ M]
pH = 3
<u>(Step 2)</u>
Determine the pOH.
pH + pOH = 14
3 + pOH = 14
pOH = 11
<u>(Step 3)</u>
Determine the hydroxide (OH⁻) concentration.
[OH⁻] = 10^-pOH
[OH⁻] = 10⁻¹¹
[OH⁻] = 1 x 10⁻¹¹ M
