All categories

2 years ago

What’s the anwser ????????????????????

Chemistry

2 answers:

bezimeni [28]2 years ago

8 0

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<h3>What is reduction?</h3>

Reduction simply refers to a half-reaction through which the number of electrons (oxidation states) that are associated with the atoms of a given chemical element are changed, especially by being reduced or decreased.

Based on this chemical reaction which occurs in a car’s catalytic converter, we can logically deduce that the oxidation state of nitrogen (N) in NO changes (decreases) from +2 to 0, and the oxidation state of carbon (C) in CO changes (decreases) from +2 to +4 as the reaction proceeds:

2NO(g) + 2CO(g) ==> N₂(g) + 2CO₂(g)

Read more on reduction here: brainly.com/question/25334331

#SPJ1

nevsk [136]2 years ago

4 0

The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.

<h3>Oxidation and reduction</h3>

Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.

In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in $N_2$ while that of C in CO changed from +2 to +4 in $CO_2$ .

Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.

More on oxidation and reduction can be found here: brainly.com/question/13699873

#SPJ1

You might be interested in

Complete and balance the precipitation reactions. Include physical states. Refer to the solubility rules as necessary. precipita

Tcecarenko [31]

The balanced chemical reactions are:

$AgNO{_3}(aq) \ + \ NaCl(aq) \rightarrow \ AgCl(s) \ + NaNO_{3}(aq)\\2K_{3}PO_{4}(aq) \ + 3MgCl_{2}(aq) \rightarrow \ 6KCl(aq) \ + Mg_{3}(PO_{4})_{2}(s)$

Further Explanation:

The following reactions will undergo double displacement where the metal cations in each compound are exchanged and form new products.

For reaction 1, the compounds involved are nitrates and chlorides. To determine the states of the products, the solubility rules for nitrates and chlorides must be followed:

All nitrates are generally soluble.
Chlorides are generally soluble except AgCl, PbCl2, and Hg2Cl2.

Therefore, the products will have the following characteristics:

silver chloride (AgCl) is insoluble
sodium nitrate (NaNO3) is soluble

For reaction 2, the compounds involved are phosphates and chlorides. The solubility rules for phosphates and chlorides are as follows:

Phosphates are generally insoluble except for Group 1 phosphates.
Chlorides are generally soluble except for AgCl, PbCl2, and Hg2Cl2.

Hence, the products of the second reaction will have the following characteristics:

potassium chloride (KCl) is soluble
magnesium phosphate is insoluble

Insoluble substances are denoted by the symbols (s) in a chemical equation. The soluble substances are denoted as <em>(aq).</em>

Learn More

Learn more about solubility brainly.com/question/1163248
Learn more about solubility rules brainly.com/question/1447161
Learn more about net ionic equations brainly.com/question/12980075

Keywords: solubility rules, precipitation reaction

3 0

3 years ago

In the reaction Na2CO3 + 2HCl → 2NaCl + CO2 + H2O, how many grams of CO2 are produced when 7.5 moles of HCl is fully reacted?

Sidana [21]

Answer:

165 of CO₂.

Explanation:

In the reaction:

Na2CO3 + 2HCl → 2NaCl + CO2 + H2O

2 moles of HCl reacts producing 1 mole o CO₂

If 7.5 moles of HCl reacts, moles of CO₂ produced are:

7.5 moles of HCl ₓ ( 1 mol CO₂ / 2 mol HCl) = 3.75 mol CO₂. As molar mass of CO₂ is 44g/mol, mass of CO₂ is:

3.75 mol CO₂ ₓ (44g / 1mol) = <em>165 of CO₂ </em>

8 0

3 years ago

Read 2 more answers

For the reaction H2PO4- HAsO4 2-HPO4 2-+H2AsO4- <br> what species are a conjugate acid-base pair?

aleksklad [387]

Ionic equation:

$\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}$

The acid and base in a conjugate pair differ by only one proton $\text{H}^{+}$ . The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

$\text{H}_2\text{PO}_4^{-}$ loses one proton to produce $\text{HPO}_4^{2-}$ in this reaction.

$\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}$

Meanwhile, $\text{HAsO}_4^{2-}$ gains one proton to form $\text{H}_2\text{AsO}_4^{-}$ .

$\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}$

Therefore

$\text{H}_2\text{PO}_4^{-}$ is the conjugate acid $\text{HPO}_4^{2-}$ , its conjugate base.
$\text{HAsO}_4^{2-}$ is the conjugate base of $\text{H}_2\text{AsO}_4^{-}$ , its conjugate acid.

8 0

3 years ago

Read 2 more answers

Help me help me please

Vadim26 [7]

Answer:

C. wind

Explanation:

4 0

3 years ago

Read 2 more answers

This chart shows descriptions of the atoms for four different substances.