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Chemistry

2 answers:

bezimeni [28]2 years ago

8 0

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<h3>What is reduction?</h3>

Reduction simply refers to a half-reaction through which the number of electrons (oxidation states) that are associated with the atoms of a given chemical element are changed, especially by being reduced or decreased.

Based on this chemical reaction which occurs in a car’s catalytic converter, we can logically deduce that the oxidation state of nitrogen (N) in NO changes (decreases) from +2 to 0, and the oxidation state of carbon (C) in CO changes (decreases) from +2 to +4 as the reaction proceeds:

2NO(g) + 2CO(g) ==> N₂(g) + 2CO₂(g)

Read more on reduction here: brainly.com/question/25334331

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nevsk [136]2 years ago

4 0

The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.

<h3>Oxidation and reduction</h3>

Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.

In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in $N_2$ while that of C in CO changed from +2 to +4 in $CO_2$ .