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iVinArrow [24]
1 year ago
14

What’s the anwser ????????????????????

Chemistry
2 answers:
bezimeni [28]1 year ago
8 0

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<h3>What is reduction?</h3>

Reduction simply refers to a half-reaction through which the number of electrons (oxidation states) that are associated with the atoms of a given chemical element are changed, especially by being reduced or decreased.

Based on this chemical reaction which occurs in a car’s catalytic converter, we can logically deduce that the oxidation state of nitrogen (N) in NO changes (decreases) from +2 to 0, and the oxidation state of carbon (C) in CO changes (decreases) from +2 to +4 as the reaction proceeds:

                    2NO(g) + 2CO(g) ==> N₂(g) + 2CO₂(g)

Read more on reduction here: brainly.com/question/25334331

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nevsk [136]1 year ago
4 0

The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.

<h3>Oxidation and reduction</h3>

Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.

In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in N_2 while that of C in CO changed from +2 to +4 in CO_2.

Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.

More on oxidation and reduction can be found here: brainly.com/question/13699873

#SPJ1

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The reactant that controls the amount of product formed in a chemical reaction is called the?
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6 0
3 years ago
ViT2 = V2T, V = V2
shusha [124]

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V₂ = 285 mL

Explanation:

Given data:

Initial volume of bag = 250 mL

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Final volume = ?

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The given problem will be solved by using Charles Law,

This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"

Mathematical relationship:

V₁/T₁  = V₂/T₂

Now we will convert the temperature into kelvin.

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Final temperature = 60.0 + 273 = 333K

Now we will put the values in formula:

V₁/T₁  = V₂/T₂

250 mL / 292K  =  V₂/ 333K

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