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iVinArrow [24]
2 years ago
14

What’s the anwser ????????????????????

Chemistry
2 answers:
bezimeni [28]2 years ago
8 0

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<h3>What is reduction?</h3>

Reduction simply refers to a half-reaction through which the number of electrons (oxidation states) that are associated with the atoms of a given chemical element are changed, especially by being reduced or decreased.

Based on this chemical reaction which occurs in a car’s catalytic converter, we can logically deduce that the oxidation state of nitrogen (N) in NO changes (decreases) from +2 to 0, and the oxidation state of carbon (C) in CO changes (decreases) from +2 to +4 as the reaction proceeds:

                    2NO(g) + 2CO(g) ==> N₂(g) + 2CO₂(g)

Read more on reduction here: brainly.com/question/25334331

#SPJ1

nevsk [136]2 years ago
4 0

The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.

<h3>Oxidation and reduction</h3>

Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.

In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in N_2 while that of C in CO changed from +2 to +4 in CO_2.

Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.

More on oxidation and reduction can be found here: brainly.com/question/13699873

#SPJ1

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Answer:

86.3 g  of N₂ are in the room

Explanation:

First of all we need the pressure from the N₂ in order to apply the Ideal Gases Law and determine, the moles of gas that are contained in the room.

We apply the mole fraction:

Mole fraction N₂ = N₂ pressure / Total pressure

0.78 . 1 atm = 0.78 atm → N₂ pressure

Room temperature → 20°C → 20°C + 273 = 293K

Let's replace data: 0.78 atm . 95L = n . 0.082 . 293K

(0.78 atm . 95L) /0.082 . 293K = n

3.08 moles = n

Let's convert the moles to mass → 3.08 mol . 28g /1mol = 86.3 g  

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