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ahrayia [7]
3 years ago
12

Cycloheptatrienone is stable, but cyclopentadienone is so reactive that it can't be isolated. Taking into account the polarity o

f the carbonyl group, draw a resonance structure of cyclopentadienone that illustrates a reason for its instability.

Chemistry
1 answer:
Lorico [155]3 years ago
3 0

Answer and Explanation:

The resonance contributor in cyclopentadienone (as shown in the attachment below) results into the compound having a positive charge on the carbonyl group, C=O which accounts for a highly reactive anti-aromatic 4π system. And this illustrates the reason for its instability.

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<h3>REFER THE ATTACHMENT ABOVE</h3>

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3 years ago
Read 2 more answers
QUESTION 3
Blababa [14]
These questions are all about indirect and direct variation with PV=nRT, the ideal gas equation

Q3.
false, because of PV=nRT, the ideal gas equation if V goes up, P has to go down to equal nRT

Q4. false, if V remains constant, and P and T are constant as moles of gas are added, then something is wrong becse something has to change when stuff is added (V has to go down)

Q5.
PV=nRT
when T and n are constant, (R is the gas constant)
PV=k, aka V=k/P which means inversly proportional

TRUE


Q6.
ggeasy
refer to past question
PV=k
if P is doubled then V has to halve in order to equal k
1/2 times 2=1
volume is halved


Q7. use charles law
V/T=k
so
given
V=4
T= kelvins, so 299
4/299=k
so when temp goes to 22 does V go to 3.95
4/299=3.95/295?
true
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Q8
FALSE, must be used in kelvins
T=absolute tempurature in kelvins


Q9
PV=nRT
solve for T
(PV)/(nR)=T

use final volumes and pressures
P=5atm
V=24L
n=1
R=0.082057 atm L/(mol K)
(5atm*24L)/(1mol*0.082057 atm L/mol K)=T
see, if you didn't mess up, the units cancel nicely
T=1462.4
1200 K is closest



Q10
PV/T=constant because moles are constant (supposedly)

V=4L
P=2.08atm
T=275K

so find initial to final is constant
(2.08atm*4L)/(275K)=(Pfinal*2.5L)/(323K)
solve for Pfinal
Pfinal=3.92315 atm
answer is 3.9atm

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Answer:

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Explanation:

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