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3 years ago

Como se realiza la salida baja en el atletismo?

Physics

1 answer:

goldfiish [28.3K]3 years ago

8 0

Answer:

Honestamente yo no se cual es la pregunta que escribiste

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Why might the plant in the dark have grown taller?

grandymaker [24]

Featured snippet from the web
Plants competing for sunlight or growing in dark conditions will develop elongated stems and poorly developed leaves. They are often tall and thin, lacking color in their stems. In severe cases, this physiological condition is called etiolation. Therefore, the darker the environment, the taller the plants tend to be

7 0

3 years ago

Are nerve cells in direct contact with other types of tissues ?<br><br> Please help.

Ber [7]

Answer:

Yes, they are.

Explanation:

it says it has to be 20 characters long so this is random.

6 0

3 years ago

A slab of glass 8.0 cm thick is placed upon a printed page. If the refractive index of the glass is 1.5, how far from the surfac

7nadin3 [17]

Answer:

5.3 cm

Explanation:

This question is an illustration of real and apparent distance.

From the question, we have the following given parameters

Real Distance, R = 8.0cm

Refractive Index, μ = 1.5

Required

Determine the apparent distance (A)

The relationship between R, A and μ is:

μ = R/A

i.e.

Refractive Index = Real Distance ÷ Apparent Distance

Substitute values in the above formula

1.5 = 8/A

Multiply both sides by A

1.5 * A = A * 8/A

1.5A = 8

Divide both side by 1.5

1.5A/1.5 = 8/1.5

A = 8/1.5

A = 5.3cm

Hence, the letters would appear at a distance of 5.3cm

8 0

3 years ago

Two blocks with rough surfaces are stacked on top of a slippery horizontal surface. The top block has a mass of m, and the botto

lapo4ka [179]

Answer:

Please refer to the attached schematic for free-body diagrams of the blocks.

The contact forces N1 = mg, N2 = 3mg.

The friction force fs = mg/2.

The tension force T = 3mg/2.

The distance y = (gt^2)/4

Explanation:

Starting with the third block which is declining a time t. Newton's Second Law implies that

$F = (3m)a\\3mg - T = 3ma\\T = 3mg - 3ma$

There are two unknowns in one equation: T and a. Therefore, we need to find more equations to solve these unknown variables.

Let's look at free-body diagram 1:

Newton's Second Law:

$F = ma\\f_s = ma$

That is another equation with one more unknown: fs.

Free-body diagram 2:

$F = (2m)a\\T - f_s = 2ma$

That is our third equation. We now have three equations with three unknowns. Combining equation 2 and 3 gives:

$T - ma = 2ma\\T = 3ma$

Plugging this equation into the first equation gives

$T = 3mg - 3ma\\3ma = 3mg - 3ma\\3mg = 6ma\\a = g/2$

Following this, we can find the other unknowns:

$T = 3ma = 3m(g/2) = \frac{3mg}{2}$

$f_s = ma = mg/2$

The contact forces are N1 and N2.

$N_1 = mg\\N_2 = 2mg + N1 = 3mg$

Finally, using the acceleration and equation of kinematics, we can find the distance the hanging weight drops in a time t.

$y - y_0 = v_0t + \frac{1}{2}at^2\\y = \frac{1}{2}(\frac{g}{2})t^2 = \frac{gt^2}{4}$

6 0

4 years ago

Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor

IgorC [24]

Answer:

A dissipates more power.

Explanation:

In a series circuit, the current is the same at any point in it.
The power dissipated in any resistor follows Joule's law, as follows:

$P = I^{2} * R$

So, for a given current, the power is directly proportional to the resistance of the resistor.
In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.

8 0

4 years ago