The total momentum of the players after collision is 130 kgm/s.
The given parameters:
- <em>Initial momentum of the returner, </em>
<em> = 0 kgm/s</em> - <em>The initial momentum of the diving player, </em>
<em> = 130 kgm/s</em>
The total momentum of the players after collision is determined by applying the principle of conservation of linear momentum as follows;

Thus, the total momentum of the players after collision is 130 kgm/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
We know that
g = LcosΘ
<span>where g, L and Θ are centripetal gravity length, and angle of object
</span><span>ω² = g/LcosΘ </span>
<span>ω = √(g / LcosΘ) </span>
Explanation:
formula for force is:
force=mass × acceleration
but in case of friction
force =coefficient of friction × Normal Reaction
F. = u × R
U = F/R
but when placed horizontally
R= M×G
M=mass=60kg
G=Gravity(10m/s or 9.8m/s)
F=140N
U=140/60×10
U=140/600
U=0.2333333333
approximately to 3 significant figures
U=0.233
if i am correct rate it 5 star