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anastassius [24]
2 years ago
14

A person hears the echo of his own voice from a distant hill after 2 seconds. How far away is the person from the hill, if the s

peed of sound is 330m/s ? ​
Physics
1 answer:
olga nikolaevna [1]2 years ago
4 0

Answer: 330 m

Explanation:

The speed of sound V is defined as the distance traveled by the sound wave d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=330 m/s is the speed of sound  

t=\frac{2 s}{2}=1 s is half the time the sound wave travels since the person speaks, the sound wave hits the hill and then returns to the person again  as an echo

d is the distance between the person and the hill

So, we have to find d:

d=Vt

d=(330 m/s)(1 s)

Finally:

d=330 m

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Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).

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3 years ago
A 4.0-m-diameter playground merry-go-round, with a moment of inertia of
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Answer:

7.1 ms⁻¹

Explanation:

d = diameter of merry-go-round = 4 m

r = radius of merry-go-round = \frac{d}{2} =  \frac{4}{2} = 2 m

I = moment of inertia = 500 kgm²

w_{i} = angular velocity of merry-go-round before ryan jumps = 2.0 rad/s

w_{f} = angular velocity of merry-go-round after ryan jumps = 0 rad/s

v = velocity of ryan before jumping onto the merry-go-round

m = mass of ryan = 70 kg

Using conservation of angular momentum

Iw_{i} - m v r = (I + mr^{2})w_{f}

(500)(2.0) - (70) v (2) = (I + mr^{2})(0)

1000 = 140 v

v = 7.1 ms⁻¹

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Answer:

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Hope this helps! 
6 0
2 years ago
Read 2 more answers
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