As per the question, the point charge is given as [q] = 6.8 C
The velocity of the charged particle [v] = 
The magnetic field [B] = 1.4 T
The angle made between magnetic field and velocity
= 15 degree.
We are asked to calculate the magnetic force experienced by the charged particle.
The magnetic force experienced by the charged particle is calculated as -
Magnetic force 
i.e F = 





Hence, the force experienced by the charged particle is C i.e 
Answer:
Explained
Explanation:
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Since angular speed is persistent, v/r is constant.
Where:
v is tangential speed;
and
r is distance from
axis.
Then equate v/r in both cases to get v in the second case.
Hence, speed = 2.2 x 2.1 / 1.4 meters
= 3.3 meters / seconds
Alternative solution would be:
w = 2.2 / 1.4 = 1.57
v = rw = 2.1 x 1.57 = 3.3 meters / seconds
<span>95 km/h = 26.39 m/s (95000m/3600 secs)
55 km/h = 15.28 m/s (55000m/3600 secs)
75 revolutions = 75 x 2pi = 471.23 radians
radius = 0.80/2 = 0.40m
v/r = omega (rad/s)
26.39/0.40 = 65.97 rad/s
15.28/0.40 = 38.20 rad/s
s/((vi + vf)/2) = t
471.23 /((65.97 + 38.20)/2) = 9.04 secs
(vf - vi)/t = a
(38.20 - 65.97)/9.04 = -3.0719
The angular acceleration of the tires = -3.0719 rad/s^2
Time is required for it to stop
(0 - 38.20)/ -3.0719 = 12.43 secs
How far does it go?
65.97 - 38.20 = 27.77 M</span>