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Vedmedyk [2.9K]
3 years ago
5

According to the law of reflection, _____.

Physics
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

states that the incident ray, the reflected ray, and the normal to the surface of the mirror all lie in the same plane. Furthermore, the angle of reflection is equal to the angle of incidence . ... This type of reflection is called diffuse reflection, and is what enables us to see non-shiny objects.

Explanation:

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Plz help ASAP I'll mark as brainliest ​
gogolik [260]

Hi there!

1.

Hooke's law states that:

F = -kx

k = Spring constant (N/m)

x = DISPLACEMENT from equilibrium (m)

Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.

2.

The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)

3.

The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.

4.

We can begin by looking at the given graph.

When the spring force = 4N, the total length of the spring is 35 cm.

Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:

35 - 30 = 5 cm.

5.1.

If the spring elongates by 10 cm, the total length of the spring is:

30 + 10 = 40 cm

According to the graph, a length of 40 cm corresponds to a force of 8N.

5.2.

We can solve for the weight of the ball using the following:

W (weight) = m (mass) · acceleration due to gravity (10N/kg)

Using a summation of forces:

∑F = T - W

The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:

0 = T - W

T = W = 8 N

5.3.

0 = T - Mg

T = Mg

Use the prior value of T and gravity to solve:

8 = 10M

m = 0.8 kg

8 0
3 years ago
Consider a series RLC circuit where R = 855 Ω and C = 6.25 μF. However, the inductance L of the inductor is unknown. To find its
sashaice [31]

Answer:

L= 0.059 mH

Explanation:

Given that

R = 855 Ω and C = 6.25 μF

V= 84 V

Frequency

ω = 51900 1/s

We know that

\omega=\sqrt{\dfrac{1}{LC}}

L=Inductance

C=Capacitance

ω =angular Frequency

ω² L C =1

(51900)² x L x 6.25 x 10⁻⁶ = 1

L= 5.99 x 10⁻⁵ H

L= 0.059 mH

6 0
3 years ago
Migratory birds are able to use the earth's magnetic field to navigate even when clouds and darkness prevent them from having vi
stealth61 [152]

Answer:

The receptors that sense the Earth's magnetic field are probably located in the birds' eyes. Now, researchers at Lund University have studied different proteins in the eyes of zebra finches and discovered that one of them differs from the others: only the Cry4 protein maintains a constant level throughout the day and in different lighting conditions

Explanation:

4 0
3 years ago
At the instant a traffic light turns green, a car starts with a constant acceleration of 1.3 m/s2. At the same instant a truck,
Bas_tet [7]

Answer:

(a) Distance traveled = 75.3846 m

(b) Velocity of car at that instant will be 14 m/sec

Explanation:

We have given acceleration of the car a=1.3m/sec^2

Initial velocity of the cart u = 0 m/sec

(a) According to second equation of motion we know that s=ut+\frac{1}{2}at^2

So distance traveled by car s_c=0\times t+\frac{1}{2}\times 1.3t^2=0.65t^2

As the truck is moving with constant speed

So distance traveled by truck s_t=ut=7t

As the truck overtakes the car

So s_c=s_t

0.65t^2=7t

t=10.769sec

So distance traveled s_c=s_t=7\times 10.769=75.3846m

(b) From second equation of motion we know that v = u+at

So v = 0+1.3×10.769 = 14 m /sec

7 0
3 years ago
Which phrase describes an atom?
kiruha [24]

You haven't included the list of choices that goes with the question, so it's
impossible for me to choose the correct one, or to help you choose it.

Regarding my ability to answer the question and collect the 5-point bounty,
I'm free to make up any phrase of my own that correctly describes an atom.

-- very very very very very very very tiny

-- includes even tinier particles, with electric charges
   both positive and negative

-- smaller than the wavelength of visible light

4 0
3 years ago
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