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3 years ago

According to the law of reflection, _____.

Physics

1 answer:

Bezzdna [24]3 years ago

6 0

Answer:

states that the incident ray, the reflected ray, and the normal to the surface of the mirror all lie in the same plane. Furthermore, the angle of reflection is equal to the angle of incidence . ... This type of reflection is called diffuse reflection, and is what enables us to see non-shiny objects.

Explanation:

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Air pollution comes from _____.

kherson [118]

Human industrialization, because without greenhouse gases the planet would be less warm

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4 years ago

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Why is a simple cell importable

densk [106]

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3 years ago

Determine the launch speed of a horizontally launched cannonball that lands 26.3

nlexa [21]

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u $\sqrt{\frac{2H}{g} }$

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/ $s^{2}$ .

So that:

26.3 = u $\sqrt{\frac{2*19.3}{9.8} }$

$(26.3)^{2}$ = $u^{2}$ x $\frac{38.6}{9.8}$

691.69 = $u^{2}$ x $\frac{38.6}{9.8}$

$u^{2}$ = $\frac{691.69*9.8}{38.6}$

= $\frac{6778.562}{38.6}$

$u^{2}$ = 175.6104

⇒ u = $\sqrt{175.6104}$

= 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

4 0

3 years ago

You're in an airplane that flies horizontally with speed 1100 km/h (300 m/s ) when an engine falls off. Neglecting air resistanc

Tcecarenko [31]

Answer:

The height of the airplane is 3312.4 meters.

Explanation:

Given that,

Speed of the airplane, v = 1100 km/h = 300 m/s

It takes 26 s for the engine to hit the ground. We need to find the height of the airplane. Using second equation of motion to find it as :

$h=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a = g

$h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times (26)^2\\\\h=3312.4\ m$

The height of the airplane is 3312.4 meters.

5 0

4 years ago

The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin

mars1129 [50]

Answer:

30 m/s

Explanation:

Velocity is $v_{final}=v_{initial}+at$ since we know that the initial velocity is 0, and the acceleration is $9.8 \frac{m}{s^2} \approx 10 \frac{m}{s^2}$ then we also know that time is 3 seconds it follows that: $v_{final}=v_{initial}+at=0+10\frac{m}{s^2}*3s=30\frac{m}{s}$

8 0

4 years ago