DescriptionElectric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of electric charge: positive and negative. Like charges repel and unlike attract. An object with an absence of net charge is referred to as neutral.
Answer:
The focal length fe of the eyepiece is <em>2.86 cm</em>
Explanation:
Since we are given the telescope's magnification and the length of the tube, we can use the expressions
<em>M = f_o/fe (1)</em> and
<em>l = f_o + fe (2)</em>
where
- M is the telescope's magnification
- l is the length of the tube
- fe is the focal length of the eye-piece
Rearranging equation (2) to make f_o the subject of the formula, we get
<em>f_o = l - fe</em>
Substituting the above equation into equation (1) we get
<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>
<em> ⇒ fe = 60/(20 + 1)</em>
⇒ <em>fe = 2.86 cm</em>
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Explanation:
A projectile is an object upon which the only force is gravity. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity. Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity.
Answer:
-969.06
-286.74
698.7
-115.6, 12.9
-139.9, 12.9
Explanation:
Given that
Speed v, wrt y = -24.3 m/s
Speed v, wrt x = 12.9 m/s
time t, = 11.8 s
a
Using the formula
H(t) = ut - 1/2gt², where u = v wrt y
H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²
H(t) = -286.74 - 682.28
H(t) = -969.06 m
b
H = ut, where u = v wrt y
H = -24.3 * 11.8
H = -286.74 m
H(1) = -969.06 - -286.74 = -682 m
c
Horizontal displacement, x = vt. Where v = v wrt x
x = 12.9 * 11.8
x = 152.22 m
d = √(H1² + x²)
d = √682² + 152²
d = 465124 + 23104
d = √488228
d = 698.7 m
d
Vertical component =
-gt - 0 =
-9.8 * 11.8 = -115.6
Horizontal component =
v wrt x - 0
12.9 - 0 = 12.9
e
Vertical component =
-gt - v wrt y =
-9.8 * 11.8 - 24.3 = -139.9
Horizontal component =
v wrt x - 0 =
12.9 - 0 = 0
Answer:

Explanation:
As we know that the tension in two strings are


now we have

so we can say


also we have


now divide two equations


