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denpristay [2]
3 years ago
7

Two students are looking at a brightly lit full Moon, illuminated by the reflected light from the Sun. Consider thefollowing dis

cussion between the two students about what the spectrum of moonlight would look like.Student
1: I think that moonlight is just reflected sunlight, so we will see the Sun’s absorption line spectrum.Student
2: I disagree.An absorption spectrum has to come froma hot, dense object. Since the Moon is not a hot, dense object, it can’t give off an aborption line spectrum.Do you agree or disagree with either or both of the students
Physics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

I agree with the student that think that moonlight is just reflected sunlight, so we will see the Sun’s absorption line spectrum.

Explanation:

Absorption spectrums occur when a white light is passed through a gas. Or simply a light from a hot source passes through a cooler gas. The moon itself is a reflection of the sun, so when it reflects the light from the sun, absorption spectrum lined can be seen. Note that it is the hot gases like hydrogen, oxygen etc in or around the sun that cause absorption spectrum.

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a liquid reactant is pumped through a horizontal, cylindrical, catalytic bed. The catalyst particles are spherical, 2mm in diame
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Answer:

The upper limit on the flow rate = 39.46 ft³/hr

Explanation:

Using Ergun Equation to calculate the pressure drop across packed bed;

we have:

\frac{\delta P}{L}= \frac{150 \mu_oU(1- \epsilon )^2}{d^2p \epsilon^3} + \frac{1.75 \rho U^2(1-\epsilon)}{dp \epsilon^3}

where;

L = length of the bed

\mu = viscosity

U = superficial velocity

\epsilon = void fraction

dp = equivalent spherical diameter of bed material (m)

\rho = liquid density (kg/m³)

However, since U ∝ Q and all parameters are constant ; we can write our equation to be :

ΔP = AQ + BQ²

where;

ΔP = pressure drop

Q = flow rate

Given that:

9.6 = A12 + B12²

Then

12A + 144B = 9.6       --------------   equation (1)

24A + 576B = 24.1    ---------------  equation (2)

Using elimination methos; from equation (1); we first multiply it by 2 and then subtract it from equation 2 afterwards ; So

288 B = 4.9

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From equation (1)

12A + 144B  = 9.6

12A + 144(0.017014) = 9.6

12 A = 9.6 - 144(0.017014)

A = \frac{9.6 -144(0.017014}{12}

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ΔP = AQ + BQ²

Given that ΔP = 50 psi

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50 = 0.5958 Q + 0.017014 Q²

Dividing by the smallest value and then rearranging to a form of quadratic equation; we have;

Q² + 35.02Q - 2938.8 = 0

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Answer:

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(02.06 LC)<br> Etiquette determines which (5 points)
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