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lbvjy [14]
3 years ago
6

A piston cylinder device contains 2kg of water at 27°c . the pressure of the system is 3 MPa. then the heat is added to the wate

r , keeping the pressure constant, until the temperature of the system reaches 340°c , during the heat addition, the volume of the cylinder is expected by 0.075m³ . determine.
1) the work done.

2) the heat addition between 27°c to 100°c.

{specific heat capacity of water-4186J/kgK​
Physics
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

asi que sobre todo lol siento soy mexican y agora no se Como escribir en ingles

soi aamso jodidamente lol siento que me enfrie want thig ror youasi que sobre todo lol siento soy mexican y agora no se Como escribir en ingles

soi aamso jodidamente lol siento que me enfrie want thig ror you

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a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

y(t) = h +u_y t - \frac{1}{2}gt^2

where

h = 2.5 km = 2500 m is the initial height

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The cargo reaches the ground when

y(t) = 0

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s

So the horizontal distance travelled is

d=v_x t

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

d=(333.3)(22.6)=7533 m = 7.5 km

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