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3 years ago

Explain why protons attached to nitrogen (i.e. n-h show broad peaks in the 1h nmr and do not couple to other protons.

1 answer:

7 0

The element Nitrogen is usually present in almost all proteins, and it also forms strong bonds due to its ability to form a triple bond with its self, also to other elements.

<span>The nitrides use a variety of different oxidation and almost all the oxides forms gasses are at 25 degrees Celsius. The oxide of nitrogen are acidic, thus, easily attaching protons.</span>

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At what speed, in m/s, would a moving clock lose 1.3ns in 1.0 day according to experimenters on the ground?

OleMash [197]

Answer:

v=0.14c

Explanation:

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3 years ago

A worker pushes a 200-N box (weight of box, you have to find mass) resting on a level floor with a force of 30 N. What is the ac

QveST [7]

For the problem we will apply the concepts related to Newton's second law. Recall that this is defined as the product between mass and acceleration, and that in special cases, when the acceleration is equivalent to the force of gravity, the force is equivalent to the weight of the person. From these relationships we will find the mass, and then the acceleration with the given force.

$F_w = mg$

Here,

$F_w$ = Force

m = Mass

g = Gravity

Replacing and rearranging we have that the mass is,

$m = \frac{F_w}{g} = \frac{200}{9.81}$

$m = 20.387kg$

Now using the value of the force, but solving for the acceleration with the previous value of the mass we have,

$F = 30N$

$a = \frac{F}{m}$

$a = \frac{30}{20.387}$

$a = 1.47m/s^2$

Therefore the acceleration of the box is $1.47m/s^2$

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3 years ago

Which of the following is a good conductor of electricity? Immersive Reader

Fofino [41]

2- Metal
explanation
metal is the only conductor listed

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4 years ago

Read 2 more answers

I need help on 11 - 14

posledela

The answer is negative three

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3 years ago

Read 2 more answers

A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an

docker41 [41]

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is $\mu=0.72$ .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

$F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N$

Acceleration , $a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2$ .

By equation of motion :

$v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s$

Therefore, the speed of box is 12.04 m/s.

Hence, this is the required solution.

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3 years ago