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aleksandrvk [35]
2 years ago
9

How many Joules of heat are released from a 400g piece of glass that has been cooled

Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
4 0

Answer:

400 × 22 × 0.664 = 5843.2 J

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Derivative for tan(x)
Maksim231197 [3]

Answer:

  • sec² (x)

Explanation:

Use the trigonometric ratio definition of the tangent function and the quotient rule.

  • tan(x) = sin(x) / cos(x)

Quotient rule: the derivative of a quotient is:

  • [the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²

  • (f/g)' = [ g×f' - f×g'] / g²

So,

  • tan(x)' = [ sin(x) / cos(x)]'
  • [ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²

                                   = [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²

                                   = [ cos²(x) + sin²(x) ] / cos²(x)

                                   = 1 / cos² (x)

                                   = sec² (x)

The result is that the derivative of tan(x) is sec² (x)

4 0
2 years ago
How many grams of MnCl2 need to be added to 5 liters of water to make a 0.25 M solution?
damaskus [11]

Answer:

I think it is 860 g MG Cl2

Explanation:

your welcome

4 0
2 years ago
Under which class of substitution reaction does this reaction appear to fall
liberstina [14]

This reaction is most likely to fall under SN2 because the thing called carbonication does not occur in SN1. The carbon forms a partial bond with the nucleophile during the intermediate phase and the leaving group. So for this question the reaction will fall under SN2.

3 0
3 years ago
Urea, CH4N2O (s), is manufactured from NH3 (g) and CO2 (g). H2O (l) is another product of this reaction. An experiment is starte
Katarina [22]

Answer:

a. 4.41 g of Urea

b. 1.5 g of Urea

Explanation:

To start the problem, we define the reaction:

2NH₃ (g) +  CO₂ (g) → CH₄N₂O (s)  +  H₂O(l)

We only have mass of ammonia, so we assume the carbon dioxide is in excess and ammonia is the limiting reactant:

2.6 g . 1mol / 17g = 0.153 moles of ammonia

Ratio is 2:1. 2 moles of ammonia can produce 1 mol of urea

0.153 moles ammonia may produce, the half of moles

0153 /2 = 0.076 moles of urea

To state the theoretical yield we convert moles to mass:

0.076 mol . 58 g/mol = 4.41 g

That's the 100 % yield reaction

If the percent yield, was 34%:

4.41 g . 0.34 = 1.50 g of urea were produced.

Formula is (Yield produced / Theoretical yield) . 100 → Percent yield

3 0
3 years ago
Match these items with their examples.
kiruha [24]
Here you go! Feel free to ask questions!

7 0
3 years ago
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