Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649
Answer:
10a+b+9c
Step-by-step explanation:
first you have to join the like terms then you add them then you write the answer, I hope you understood
9c+5a+5a+b
9c+10a+b
10a+b+9c
Answer:
a. The arm spans for Class A have more variability than the arm spans for Class B.
Step-by-step explanation:
The stemplot for the Arm span is given for Class A and Class B. The variability of Class A are higher than variability of Class B. The arm spans of Class A have values greater than Class B. The mean of Class A is greater than Class B.
The one u originally clicked (in yellow) is correct. all sides match perfectly with the figure.