Answer:
It should be the first one.
Step-by-step explanation:
Answer:
yES 2:3
Step-by-step explanation:
The sides are the same length
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Here it is in order (2nd to 6th):
1/ab, 1/a^3, b/a^5, b^2/a^7, b^3/a^9
Hope this helps!
L = Length
W = Width
L x W = area
Length = 2w
Lets find the width by solving for w.
2w + w = 36
3w = 36
3w/3 = 36 / 3
w = 12
So
L = 2 x 12 = 24
W = 12
L X W = area
24 x 12 = 288 cm^2