Considering that the data has no outliers, the mean of 3.2 inches should be used to describe the center of the data represented in this line plot.
<h3>What measure should be used to describe the center of a data-set?</h3>
It depends if the data-set has outliers or not.
- If it does not have outliers, the mean should be used.
- If it has, the median should be used.
The dot plot gives the number of times each measure appears. Since there is no outliers, that is, all values are close, the mean should be used. It is given by:
M = (2 x 1 + 3 x 2 + 2 x 3 + 1 x 5 + 1 x 6 + 1 x 7)/(2 + 3 + 2 + 1 + 1 + 1) = 3.2 inches.
The mean of 3.2 inches should be used to describe the center of the data represented in this line plot.
More can be learned about the mean of a data-set at brainly.com/question/24628525
28 times 5 because volume= length times width times height. Brainliest?
14...I need them points so I’m answering
Answer:
(√6)/2 square units
Step-by-step explanation:
The area of a triangle is half the magnitude of the cross product of the vectors representing adjacent sides.
QR = (4-3, -1-(-4), -4-(-5)) = (1, 3, 1)
QS = (3 -3, -5-(-4), -6-(-5)) = (0, -1, -1)
The cross product is the determinant ...
The magnitude of this is ...
|QR × QS| = √((-2)² +1² +(-1)²) = √6
The area of the triangle is half this value:
Area = (1/2)√6 . . . . square units
21d+.23x (d being per day) (x being every mile above 125)
