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yan [13]
3 years ago
9

What is the volume of 45g of benzene, C6H6 at 100°C and 250 Torr?

Chemistry
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

V = 53.82 L

Explanation:

Given data:

Mass of benzene = 45 g

Temperature = 100°C (100+273 = 373 K)

Pressure = 250 torr (250/760 = 0.33 atm)

Volume of benzene = ?

Solution:

Number of moles of benzene:

Number of moles = mass /molar mass

Number of moles = 45 g/ 78.11 g/mol

Number of moles = 0.58 mol

Volume of benzene:

PV = nRT

V = nRT/P

V = 0.58 mol × 0.0821 atm.L/mol.K × 373 k / 0.33 atm

V = 17.76 atm.L /0.33 atm

V = 53.82 L

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Please help me with chemistry
vodka [1.7K]

Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

Mass = % * sample atomic mass

Mass = 79% * 24

Mass = (79/100) * 24

Mass = 18.96

<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


7 0
3 years ago
True or False. Solutions for which water is the solvent are called aqueous solutions.
Stolb23 [73]
This is true. Water is the solvent in aqueous solutions
5 0
3 years ago
How do you separate iron and steel from the industrial waste
Volgvan

Iron and steel are magnetic in nature. So you can use a magnet to separate them

5 0
3 years ago
A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
4 years ago
What is the correct name for the chemical formula N408?
Alexandra [31]

Answer:

molar mass (molar weight)

Explanation:

7 0
3 years ago
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