<span>PV = nRT
moles of H2 = 1/2 = 0.5
moles of He = 1/4 =0.25
T = 273 + 27
partial pressure of H2
Px1 = 0.5x0.083x300
P=12.45 atmospheres
PP of He
px1 = 0.25x0.083x300
P =6 22 atmospheres
Totla pressure = 6.22 + 12.45 = 18.68 atm</span>
Answer:
162 KJ
Explanation:
The electrical energy can be calculated using the formula
E = V×I×t
Where, V= voltage = 120 V
I is current in ampere = 7.5 A and t is time in seconds
1 hour = 3600 sec
Therefore, 0.05 hour = 3600×0.05 = 180 sec
Substitute the values in above equation find electrical power
E = 120×7.5×180
= 162000 J
= 162 KJ
Therefore, the electrical energy use of the microwave = 162 KJ
Answer:
= 1.46 × 10 ¹⁰ electron
Explanation:
Given that
E, Electric field = 1000N/C
D, Diameter = 29cm
r, radius = 0.145
E = kq/r²
→ q = Er²/k
q = (1000 × (0.145)² ) / (9 × 10⁹)
q = 2.34 × 10⁻⁹C
q = Ne
where e = 1.6 × 10⁻¹⁹
N = (2.34 × 10⁻⁹) / (1.6 × 10⁻¹⁹)
= 1.46 × 10¹⁰ electron
Answer:
288/10=28.8kg is the correct answer hope it helps
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2