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kkurt [141]
3 years ago
15

A block with mass m1 = 8.8 kg is on an incline with an angle θ = 41.0° with respect to the horizontal. For the first question th

ere is no friction, but for the rest of this problem the coefficients of friction are: μk = 0.39 and μs = 0.429.. . . . To keep the mass from accelerating, a spring is attached. What is the minimum spring constant of the spring to keep the block from sliding if it extends x = 0.13 m from its unstretched length. . . . . Now a new block with mass m2 = 16.4 kg is attached to the first block. The new block is made of a different material and has a greater coefficient of static friction is needed between the new block and the plane to keep the system from accelerating?
Physics
1 answer:
serg [7]3 years ago
6 0
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2
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Answer:

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Explanation:

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YP= mP / 100 kg =  46.835 kg / 100 kg = 46.835 %

YP= 46.835 %

the concentration of solids Cs is

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V = 10.88 m/s

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using the equation

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