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2 years ago

Calculate the electrical energy use of the microwave in 120 V circuit has 7.5 A current flow, if it used for 0.05 hours

Physics

1 answer:

Elden [556K]2 years ago

3 0

Answer:

162 KJ

Explanation:

The electrical energy can be calculated using the formula

E = V×I×t

Where, V= voltage = 120 V

I is current in ampere = 7.5 A and t is time in seconds

1 hour = 3600 sec

Therefore, 0.05 hour = 3600×0.05 = 180 sec

Substitute the values in above equation find electrical power

E = 120×7.5×180

= 162000 J

= 162 KJ

Therefore, the electrical energy use of the microwave = 162 KJ

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label the three planes and axis of movement on the figures. define each plane and axis of movement and axis of movement and give

TiliK225 [7]

Answer: it = kobe

Explanation

5 0

2 years ago

LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.

Svetradugi [14.3K]

Answer:

i) E = 269 [MJ] ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

$E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.$

$W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]$

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

$E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]$

8 0

2 years ago

If i apply 280 n of force to a 40kg object, what will it's acceleration be?

nika2105 [10]

Answer:

f=ma

f=280N

m=40kg

a=?

280=40a

a=280/40

a=70N/kg

6 0

3 years ago

32. Which type of electromagnetic wave is used for nuclear power and medical treatment?

adelina 88 [10]

Answer:

Answers at the bottom!!

Explanation:

For the first answer: Gamma ray

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

For the second answer: They both have technological uses.

In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.

Hope this helps!!

Happy Holidays and Season Greeting!!

ii Feliz Navidad a todos !!

3 0

2 years ago

The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins

krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation: