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3 years ago

Calculate the electrical energy use of the microwave in 120 V circuit has 7.5 A current flow, if it used for 0.05 hours

Physics

1 answer:

Elden [556K]3 years ago

3 0

Answer:

162 KJ

Explanation:

The electrical energy can be calculated using the formula

E = V×I×t

Where, V= voltage = 120 V

I is current in ampere = 7.5 A and t is time in seconds

1 hour = 3600 sec

Therefore, 0.05 hour = 3600×0.05 = 180 sec

Substitute the values in above equation find electrical power

E = 120×7.5×180

= 162000 J

= 162 KJ

Therefore, the electrical energy use of the microwave = 162 KJ

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How do you find the water pressure at the bottom of the 55-m-high water tower?

svp [43]

-- What's the volume of a cylinder with radius=1m and height=55m ?

   ( Volume of a cylinder = π R² h )

-- How much does that volume of water weigh ?

    1 liter of water = 1 kilogram of mass
Weight = (mass) x (acceleration of gravity)

-- What's the area of the bottom of that 1m-radius cylinder ?

   Pressure = (force) / (area)

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3 years ago

What's the minimum Out PUT WORK<br> required to raise 14,0m3 of water 26.0m?

BartSMP [9]

Answer:

3.57 MJ

Explanation:

ASSUMING it's fresh water with density of 1000 kg/m³

W = ΔPE = mgΔh = 14.0(1000)(9.81)(26.0) = 3,570,840 J

Salt water would require more.

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3 years ago

1. A car is stopped at a red light. When the light turns green, the car starts

Lubov Fominskaja [6]

Answer:

Because of inertia (Newton's First Law of motion)

Explanation:

According to Newton's First Law of motion:

"An object at rest (or in motion at constant velocity) will tend to stay at rest (or tend to keep moving with same velocity) unless acted upon an unbalanced force"

In this problem, the object we are analyzing is the coffee cup.

At the beginning, the cup is at rest, together with the car.

Later, the car starts moving when the light turns green.

If we apply Newton's First Law of motion to the cup, we see that the coffee cup tends to keep its state of rest: for this reason, as the car moves forward, the coffee in the cup will spill backward, into the rear seat. This property of an object to mantain its state of motion is also called as inertia.

8 0

3 years ago

A total resistance of 3.03 Ω is to be produced by connecting an unknown resistance to a 12.18 Ω resistance. (a) What must be the

insens350 [35]

Answer:

(a) 4.0334Ω

(b)parallel

Explanation:

for resistors connected in parallel;

$\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}$

Req =3.03Ω , R1 =12.18Ω

$\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}$

$\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}$

$\frac{1}{R2}=0.2479$

R2=1/0.2479

R2=4.0334Ω

(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.

Req = R1+R2

3 0

3 years ago

A girl throws a marshmallow that lands in her friend’s mouth 2 m away. The girl threw the marshmallow at an angle of 30 degrees.

natima [27]

She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.

<h3>What is projectile motion?</h3>

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

Given data;

The marshmallow was thrown at a distance of 2 meters

Range,R = 3 m

Initial velocity,u

The angle at which the marshmallow was thrown,θ = 30°

The acceleration due to gravity,g = 9.81 m/s²

The projectile's motion is divided into two parts: horizontal and vertical motion.

$\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec$

Hence, she throws the marshmallow at a speed of 4.76 m/sec.

To learn more about the projectile motion refer to the link;

brainly.com/question/11049671

#SPJ1

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2 years ago