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3 years ago

How many protons, electrons, and does chromium have?

1 answer:

8 0

Cr(chromium) is number 24, meaning that it has 24 protons, and 24 electrons. You subtract the atomic number from the atomic mass to get the number of neutrons. 50-24=26 neutrons. There are other isotopes that have more neutrons, as the mass on the periodic table is 52.

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A box is pushed horizontally with 30N for 3m. How much work was done?

maxonik [38]

90, since W=FxD so 30x3 is 90.

3 0

3 years ago

What might be done to prevent acid rain damage to objects made from metal and carbonate, such as limestone? Identify a metal obj

serg [7]

Answer: Bronze is a metal that can be damaged in acid rain. It is harsh to metals by almost burning them and may create rust. Everbrite is a clear, protective coating that will seal metal and bronze.

Explanation:

I know this is correct i have done all the research

7 0

3 years ago

Two asteroids collide and stick together. The first asteroid has mass of 1.50 × 104 kg andis initially moving at 0.77 × 103 m/s.

KengaRu [80]

Answer:

Magnitude 900m/s, direction 12.8° respect to the velocity of the first asteroid.

Explanation:

This is a perfectly inelastic collision, because the two asteroids stick together at the end. That means that the kinetic energy doesn't conserves, but the linear momentum does. But, since the velocities of the asteroids have different directions, we have to break down them in components. For convenience, we will take the direction of the first asteroid as x-axis, and its perpendicular direction (in the plane of the two velocity vectors) as y-axis. So, we have that:

$p_{1ox}+p_{2ox}=p_{fx}\\\\p_{2oy}=p_{fy}$

And, since $p=mv$ , we get:

$m_1v_{1o}+m_2v_{2o}\cos\theta=(m_1+m_2)v_{fx}\\\\m_2v_{2o}\sin\theta=(m_1+m_2)v_{fy}$

Solving for v_fx and v_fy, and calculating their values, we get:

$v_{fx}=\frac{m_1v_{1o}+m_2v_{2o}\cos\theta}{m_1+m_2}\\\\\implies v_{fx}=\frac{(1.50*10^{4}kg)(0.77*10^{3}m/s)+(2.00*10^{4}kg)(1.02*10^{3}m/s)\cos20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=878m/s\\\\\\v_{fy}=\frac{m_2v_{2o}\sin\theta}{m_1+m_2}\\\\\implies v_{fy}=\frac{(2.00*10^{4}kg)(1.02*10^{3}m/s)\sin20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=199m/s$

Now, the final speed can be calculated using the Pythagorean Theorem:

$v_f=\sqrt{v_{fx}^{2}+v_{fy}^{2}} \\\\\implies v_f=\sqrt{(878m/s)^{2}+(199m/s)^{2}}=900m/s$

And the direction $\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°$ can be obtained using trigonometry:

$\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°$

That means that the final velocity of the two asteroids has a magnitude of 900m/s and a direction of 12.8° with respect to the velocity of the first asteroid.

7 0

3 years ago

A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.

stepladder [879]

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

$v_x = v_0 cos \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_x = (16 m/s) cos 63^{\circ}=7.3 m/s$

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

$v_y = v_0 sin \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_y = (16 m/s) sin 63^{\circ}=14.3 m/s$

6 0

3 years ago

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and the

MissTica

Answer:

V = 10581.59 V

Explanation:

To solve this problem, we have to take into the relation between the kinetic energy of an electron and the energy generated by the potential difference of an electric field. This relation is given by

$E_{k} = E_{V}$

$\frac{1}{2}mv^{2} = eV$

where m is the mass of the electron, v is the velocity of the electron, e is the electric charge and V is the potential difference that accelerated the electron.

By taking V from the last expression we have:

$V = \frac{mv^{2}}{2e} = \frac{(9.1*10^{-31} )(6.1*10^{7})^{2}}{2*(-1.6*10^{-19})}} = 10581.59 V$

where we have taken that

me = 9.1*10^(-31) Kg

e = -1.6*10^(-19) C

v = 6.1*10^(7)

I hope this is useful for you

Regards

6 0

4 years ago