Fusion:

Why must oxidation be accompanied by a reduction?

Crazy boy [7]

Answer:

A

Explanation:

because the species being oxidized shares electrons with the species that is reduced.making the oxidized element positively charged and the reduced element negatively charged.

I hope this helps

5 0

3 years ago

Read 2 more answers

Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 35.6 g?

lys-0071 [83]

Answer:

45.069 mL

Explanation:

mass/density=volume.

If we fill in the numbers provided, we would have:

35.6/0.7899=45.069

Don't forget to add your measurements!

45.069 mL

3 0

3 years ago

Electrons are capable of emmiting engery in the form of light at very narrow ranges of wavelengths. these wavelengths can be mea

sukhopar [10]

C) energy level

Looking at quantum mechanics, we see that electrons exist at certain energy levels. When they get excited, they’ll jump from one energy state to a higher energy state and down. We can the. Look at the color it admits and determine what the energy level is.

5 0

3 years ago

CH3OH can be synthesized by the following reaction.

puteri [66]

Answer:

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

Explanation:

Step 1: Data given

CO(g)+2H2(g)?CH3OH(g)

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.04 g/mol

Step 2: What volume of H2 gas (in L), measured at 754mmHg and 90?C, is required to synthesize 23.0g CH3OH?

Pressure = 754 mmHg = 0.992 atm

Temperature = 90°C = 363 Kelvin

mass of CH3OH produced = 23.0 grams

Step 3: Calculate moles of CH3OH

Moles CH3OH = mass CH3OH / Molar mass CH3OH

Moles CH3OH = 23.0 grams / 32.04 g/mol

Moles CH3OH = 0.718 moles

Step 4: Calculate moles of H2

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

For 0.718 moles CH3OH produced, we have 2*0.718 moles =1.436 moles of H2 and 0.718 moles of CO

Step 5: Calculate volume of H2

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 1.436 moles H2

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (1.436*0.08206*363)/0.992

V = 43.12 L

Step 6: Calculate volume of CO

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 0.718 moles CO

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (0.718*0.08206*363)/0.992

V = 21.56 L

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

3 0

4 years ago

I need help with organic chemistry!!!

nadya68 [22]

Answer:

CHO2- ion

Explanation:

We have the lewis structure of a formate-ion here

This is CHO2-.

The carbon atom is the central atom in the structure. It's the least electronegative atom (C). Carbon has 4 valence electrons. Oxygen has 6 valence electrons.

The carbon will bind with 1 hydrogen atom, this will form 1 single bond, because hydrogen has 1 valence electron.

The carbon will bind with oxygen via a double bond.

Since carbon has only 4 valence electrons, it can only form 1 bond with the other oxygen atom.

There will formed 1 double bond between C and O and 1 single bond between C and O resulting in a negative charged O-atom.

This means there are two resonance structures. for the CHO2- ion

7 0

3 years ago