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pickupchik [31]
3 years ago
11

You note that cells placed in a solution crenate. What could you definitively conclude about the solution?

Chemistry
2 answers:
lys-0071 [83]3 years ago
6 0

Answer:it means the cell is an hypertonic or high concentration solution

Explanation: osmosis is defined as movement of water from a region of high concentration to a region of low concentration of water.

Now being in a hypertonic solution means the sorrounding solution in a high concentration of the solute which means water is in low in concentration , so osmotic pressure move water from the cell (which has a relatively higher water concentration )to it's sorrounding which has a lower concentration of water, resulting in the shrinking or crenation of the cells.

Likurg_2 [28]3 years ago
4 0

Answer:Conclusion: The solution is hypertonic in nature.

Explanation:

when a cell is exposed to a hypertonic solution,cell will crenate,that is contraction of cell occurs.This is because water moves from the cell to the surrounding via osmosis as result cell shrinks and an abnormal notchings occurs in its membrane.

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Need help with 14 and 16 pls asap!! this is my friends test and im taking it tomorrow!!
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Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

<u><em>Q14:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

<u><em>Q16:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

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3 years ago
At what temperature will 2.50 moles of ideal
Sever21 [200]

Answer: 1,218K

Explanation:

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