$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
Answer:
# 1,3 and 6
Step-by-step explanation:
Answer:
classical music
Step-by-step explanation:
i suggest beetoven for classicla and for rock the rock
Answer:
Jimmy has one candy times, 35 candies that his mom just gave him. He said, he's going togive 14 out of the 16 candies, he put a side to his mom