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Artyom0805 [142]
3 years ago
12

A uniform metre rule of mass 10g is balanced on a knife edge placed at 45cm mark. Calculate the distance of a mass 25g from the

pivot​
Physics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

The distance of a mass 25g from the pivot​ is 18cm

Explanation:

Given

m_1 = 10g

d_1 = 45cm

m_2 = 25g

Required

Distance of m2 from the pivot

To do this, we make use of:

m_1 * d_1 = m_2 * d_2 --- moments of the masses

So, we have:

10 * 45= 25* d_2

450= 25* d_2

Divide both sides by 25

18= d_2

Hence:

d_2 = 18

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755 x 10⁻⁷ m

Explanation:

D = distance of screen

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wave length λ = 566 nm

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= 3.00 x 10⁻² =2 λD /d

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Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.
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1.312 x 10⁻¹² J/nucleon

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mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x  1.00728 amu + 80 x 1.00867 amu

                      = 137.10128 amu

mass defect = 137.10128 - 135.905

                    = 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

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