Burning, a sour taste, and usually donating hydrogen ions to other substances.
11. Density of the piece of wood = 3000 g/cm³
12. Density of wooden block = 2 g/cm³. and it will not float in water.
13. Volume of the plastic ball should be 250 mL
14. Mass of the ice cube = 0.162 g
15. Volume of gasoline spilled is equal to 2000 mL
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Explanation:</h3><h3>
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11.
<u>Formula:</u>
Given:
Mass of wood piece = 7500 g
Volume of wood piece = 2.5 cm³
Therefore,
Density of the piece of wood = 3000 g/cm³
12.
<u>Formula:</u>
Given:
Dimensions of wooden block = length × width × height = 5 cm × 4 cm × 2 cm
Mass = 80.0 g
Volume of wooden block =
Therefore,
Density of wooden block = 2 g/cm³.
Density of water is equal to 1 g/cm³
2 g/cm³ > 1 g/cm³
Since density of wooden block is greater than the density of water, the piece of wood will not float in water. It will sink.
13.
<u>Formula:</u>
Given:
Mass of the ball = 125 g
Density = 0.5 g/mL
Therefore,
Volume = 250 mL
Volume of the plastic ball should be 250 mL
14.
<u>Formula:</u>
Given:
Dimensions of ice cube = length × width × height = 3 cm × 3 cm × 3 cm
Density = 0.006 g/mL
Volume of ice cube =
Since,
Therefore,
Mass of the ice cube = 0.162 g.
15.
<u>Formula:</u>
Given:
Mass of gasoline = 1330 g
Density = 0.665 g/mL
Therefore,
Volume = 2000 mL
Volume of gasoline spilled is equal to 2000 mL
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°