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konstantin123 [22]
2 years ago
15

The symbol for the hydroxide ion is

Physics
2 answers:
inn [45]2 years ago
6 0
I believe it’s OH have a good day
musickatia [10]2 years ago
5 0
It is OH and it has a charge of negative 1
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Alex_Xolod [135]

Answer:

The proton has much greater mass

Explanation:

  • Protons and electrons are part of an atom
  • Proton exists inside nucleus whereas electron keep moving around the nucleus
  • Electrons have negative charge where as protons have positive charge .
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I WILL GIVE BRAINLIEST
11111nata11111 [884]

Answer:

A, B, F

Explanation:

I believe these are the answers, sorry if it is incorrect.

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3 years ago
Natalie lifts a 15-kg rock from the ground onto a 1.5 meter high wall. what is the amount of potential energy she has given the
Zina [86]
The amount of gravitational potential energy acquired by the rock is equal to:
\Delta U = mg \Delta h
where 
m is the mass of the rock
g is the gravitational acceleration
\Delta h is the increase in height of the rock

Substituting the data of the problem, we find
\Delta U=(15 kg)(9.81 m/s^2)(1.5 m)=220.7 J
So, Natalie gave 220.7 J of energy to the rock.
4 0
3 years ago
A sample of gold has a mass of 30.94 grams and density of 19.32g/cm^3. What volume of space will this sample of gold occupy?
sdas [7]
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3

Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3

Then, the answer is the option C. 
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3 years ago
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A vertical spring has a length of 0.25 m when a 0.175 kg mass hangs from it, and a length of 0.775 m when a 2.075 kg mass hangs
Contact [7]

Answer:

A) 35.5N/m b) 20.1cm

Explanation:

Using Hooke's law;

F = Ke where F is the weight of the object = mass of the object in kg * acceleration due to gravity in m/s^2 and k if the force constant of the spring in N/m and e is the extension of the spring which original length of the spring - new length after extension in meters

For the first body, m*g = K * (0.25- li)

Where li is the initial length of the spring

0.175*9.81 = k(0.25-li)

1.72 = k(0.25-li) as equation 1

For the second body, m *g = K* ( 0.775-li)

2.075*9.81 = k (0.775-li) equation 2

20.36 = k(0.775-li)

Make li subject of the formula;

li = 0.775 - 20.36/k

Substitute for li in equation 1

1.72 = k(0.25- (0.775 - 20.36/k))

1.72 = k ( 0.25 - 0.775 + 20.36/k)

Open the bracket with k

1.72 = 0.25k - 0.775k + 20.36 (since k cancel k)

Collect the like terms:

1.72 - 20.36 = - 0.525k

- 18.64 = -0.525k

Divide both side by -0.525

-18.64/-0.525 = -0.525/-0.525k

K = 35.5N/m

B) substitute for k in using

li = 0.775 - 20.36/k

li = 0.775 - 20.36/35.5

li = 0.775 - 0.574

li = 0.201 in meters

li = 0.201 * 100 centimeters = 20.1cm

4 0
3 years ago
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