Answer:
A‘‘ (1,6)
Step-by-step explanation:
after a reflection about a horizontal line the x coordinates remain the same
the middle point of the segment AA’ lies on the line so it has y = -1
so we have
(y+y’)/2 = -1
y’ = -2 -y
y‘ = -2 -2 = -4
so A‘ (1,-4)
we can use the same reasoning to find the reflection about y = 1
x‘ = x
(y + y’)/2 = 1
y‘ = 2+4
y’ = 6
A‘‘(1,6)
Answer:
It would be $ 564,300 so C
Step-by-step explanation:
just took the test
Answer:
Look at the unfolded cylinder down: it's consisted of a rectangle and 2 circles. so to find the surface area of the cylinder we should find the areas of the rectangle and the 2 circles.
1) A of 2 circles = 2(π
) = 2π
2) A of rectangle = base x height (or length x width) = bh
but the if we fold the rectangle? what will happen?
the base will go around the circle, this means that the base is equal to the circle circumference, which is 2πr.
Therefore, A of rectangle = 2πrh
3) Surface area of cylinder = 2π
+ 2πrh
simplify more and take the common factor 2πr:
= 2πr (r+h)
Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:

Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:

b) The mean and variance of defective components in the sample is:

The Chebyschev's inequality established:
