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slavikrds [6]
3 years ago
14

Which of the following statements is true? A. Democritus discovered the proton. B. Dalton discovered the proton. C. Thomson disc

overed the electron. D. Rutherford discovered the neutron.
Chemistry
1 answer:
iren2701 [21]3 years ago
8 0

It’s C.thomson discovered the electron

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If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?
Serhud [2]

Answer:

https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186

Explanation: Thats your answer

3 0
2 years ago
How much energy is evolved during the formation of 197 g of Fe, according to the reaction below?
hoa [83]

Answer:

ΔH for formation of 197g Fe⁰ = 1.503 x 10³ Kj => Answer choice 'B'

Explanation:

Given Fe₂O₃(s) + 2Al⁰(s) => Al₂O₃(s) + 2Fe⁰(s) + 852Kj

197g Fe⁰ = (197g/55.85g/mol) = 3.527 mol Fe⁰(s)

From balanced standard equation 2 moles Fe⁰(s) => 852Kj, then ...

3.527 mole yield (a higher mole value) => (3.527/2) x 852Kj = 1,503Kj (a higher enthalpy value).

______

NOTE => If 2 moles Fe gives 852Kj (exo) as specified in equation, then a <u>higher energy value</u> would result if the moles of Fe⁰(s) is <u>higher than 2 moles</u>. The ratio of 3.638/2 will increase the listed equation heat value to a larger number because 197g Fe⁰(s) contains more than 2 moles of Fe⁰(s) => 3.527 mole Fe(s) in 197g.  Had the problem asked for the heat loss from <u>less than two moles Fe⁰(s)</u> - say 100g Fe⁰(s) (=1.79mole Fe⁰(s)) - then one would use the fractional ratio (1.79/2) to reduce the enthalpy value less than 852Kj.  

8 0
2 years ago
Select all of the answers that apply.
shtirl [24]
The odysseyware answer is the same as his wood manure and food crops
5 0
3 years ago
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Which sample would serve as a better buffer and therefore a better environment for aquatic life?
Ann [662]

Answer:

sample A

Explanation:

the first one because of the ppm value

6 0
1 year ago
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What is the percentage of lithium in lithium carbonate (Li2CO3)?
ale4655 [162]
Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g


% LI = 13.88/73.89*100 = 18.78% perfectly correct.
6 0
2 years ago
Read 2 more answers
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