Answer:
0.35 g of H₂O
Explanation:
Firstly we have to make the reaction's equation.
In this case, the reactants are HBr and NaOH and the products are water and NaBr. This is a neutralization reaction.
We calculate the moles of each reactant:
1.6 g / 80.9 g/mol = 0.0198 moles of HBr
1.15 g / 39 g/mol = 0.0295 moles of NaOH
Reaction: NaOH + HBr → NaBr + H₂O
Ratio is 1:1, so the limiting reactant is the hydrobromic acid.
For 0.0295 moles of hydroxide we need the same amount of acid, but we do not have enough HBr, just 0.0198 moles.
Ratio is 1:1, again. 1 mol of acid can produce 1 mol of water.
Therefore, 0.0198 moles of HBr will produce 0.0198 moles of water.
We convert the moles to mass → 0.0198 mol . 18 g/mol = 0.35 g of H₂O
