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2 years ago

Molarity s defined as the

Chemistry

2 answers:

dem82 [27]2 years ago

7 0

The answer is #2
Hope I helped

RideAnS [48]2 years ago

3 0

The molar concentration of a solution, usually expressed as the number of moles of solute per liter of solution.

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How many moles are in 1.20 times 10^25 atoms of phosphorus

Stels [109]

19.927 moles are in 1.20 times $10^{25}$ atoms of phosphorus.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others.

1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .

Moles= $\frac{Atoms}{\;Avogadro's \;number }$

Moles= 1.20 X $10^{25}$ atoms ÷ 6.022 X $10^{23}$

= 19.927

Hence, 19.927 moles are in 1.20 times $10^{25}$ atoms of phosphorus.

Learn more about moles here:

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1 year ago

An element with 7 valence electrons will most likely

ss7ja [257]

Answer:

An element with 7 valence electrons will most likely be a halogen and gain an electron

Explanation:

6 0

2 years ago

The reaction is first order in cyclopropane and has a measured rate constant of k=3.36×10−5 s−1 at 720 k. if the initial cyclopr

sergey [27]

Answer:

0.0277 M.

Explanation:

The integral rate law of a first order reaction:

where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,

t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,

[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>

∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]

Taking the exponential of both sides:

1.6 = (0.0445 M)/[A]

<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>

<em />

6 0

2 years ago

You need to prepare 1 L of the citric acid/citrate buffer. You have chosen to use Method 1 (see lab presentation). Calculate the

prisoha [69]

Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid]

<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

<em>Moles HX and NaX:</em>

Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

Moles HX = 0.300L * (0.45mol / L) = 0.135 moles HX - 0.065 moles NaOH = 0.070 moles HX

Replacing in H-H equation:

pH = 3.14 + log [0.065mol] / [0.070mol]

pH = 3.11 is the pH of the buffer

8 0

2 years ago

What is the answer to this question

kvasek [131]

Answer:

b. double bonds, triple bonds, carbon atoms,and hydrogen atoms.

Explanation:

<h2>please mark me brainliest</h2>

3 0

2 years ago