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S_A_V [24]
3 years ago
5

In an endothermic reaction, heat is absorbed from the surroundings. How does this affect entropy?

Chemistry
2 answers:
stealth61 [152]3 years ago
5 0

Answer:

D. The particles in the surroundings move slower and have decreased entropy.

Explanation:

Educere/Founder's Education answer

balandron [24]3 years ago
4 0

Answer: -

Thus the entropy of the particles in the surroundings move slower and have decreased entropy.

Explanation: -

In an endothermic reaction, heat is absorbed from the surroundings.

So the particles in the surroundings lose energy to the system during an endothermic reaction.

Due to a loss in their kinetic energy, the particles move slower.

Thus the entropy of the particles in the surroundings move slower and have decreased entropy.

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¿Qué ocurre cuando la radiación del sol atraviesa la atmósfera?
12345 [234]
Umm yo no se no ablo engles
6 0
2 years ago
Please help I need these answers
Burka [1]

Answer:

2 a

element pure form cannot broken down

3 b

Chemical change chemical R×N

(R×N = reaction)

4c homogeneous solution

Yield = Yield (reaction yield): A measure of a chemical reaction's efficiency, as a ratio of moles of product to moles of reactant. Usually expressed as a percentage. % Yield = Moles of product.

Explanation:

5 0
2 years ago
How would you prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL
hoa [83]
<h2>Step 1 : Identify the given </h2>

Volume = 250mL

Density = 1.19 g/ML

<h2>Step 2 . Calculate the mass of HCL </h2>

Density = mass/volume

∴Mass = Density * Volume

= 1.19g/mL* 250mL

= 297,5g

<h2>Step 3 : Calculate the total mass of the solution, given that concentration HCL is 38% </h2>

Mass of the total solution can be calculated by the following :

38% = Mc /297.5 * 100

Mc = 38/100 *297.5

= 113.05grams

• Finally, this means that mass of the total solution of 0.125M HCL i,s 113grams, ,you would use this mass to prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0%

6 0
1 year ago
If the distance between a point charge and a neutral atom and is multiplied by a factor of 5, by what factor does the force on t
dexar [7]

Given :

The distance between a point charge and a neutral atom and is multiplied by a factor of 5.

To Find :

By what factor does the force on the neutral atom by the point charge change.

Solution :

We know, electrostatic force between two object is directly proportional to product of charge and inversely proportional to distance between them.

Now, charge in neutral atom is 0 C.

So, the electrostatic force between two of them is also 0 N.

Therefore, by changing distance between the charge the forces did no change ( it remains zero).

3 0
3 years ago
PLEASE ANSWER
PolarNik [594]
I think its A.
if one force cannot overcome the other, the object remains stationary.
4 0
3 years ago
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