Can someone help me find the area? i will give brainlist!
1 answer:
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Question:
The image of the question is attached below.
Answer:
x = 40
Solution:
Given ΔVDG ΔVNG.
DG = 207, NQ = 138, GQ = 60, QV = x
In two triangles are similar, then the measures of the corresponding sides are in proportional to each other.
Do cross multiplication, we get
Divide by 207 on both sides of the equation, we get
⇒ x = 40
⇒ QV = 40
Hence the value of x is 40.
Answer:
y= -2x-5
Step-by-step explanation:
First find the gradient of the first line
m=
m=
m=1/2
From this we can find the gradient of the perpendicular line, or the normal.
m1 × m2 = -1
Replace m1 with 1/2
1/2 × m2 = -1
m2= -2
Substitute values into
y-y1=m (x-x1)
y-3=-2 (x+4)
y-3=-2x -8
y=-2x-5