Answer:
The molarity of the potassium hydroxide solution is 0.104 M
Explanation:
Step 1: Data given
Molarity of hydrobromic acid (HBr) = 0.122 M
Volume of potassium hydroxide (KOH) = 22.1 mL = 0.0221 L
Volume of hydrobromic acid = 18.8 mL = 0.0188 L
Step 2: The balanced equation
HBr(aq) + KOH(aq) → KBr(aq) + H2O(l)
Step 3: Calculate moles of HBr
Moles HBr = molarity HBr * volume HBr
Moles HBr = 0.122 M * 0.0188 L
Moles HBr = 0.0022936 moles
Step 4: Calculate molarity of KOH
We need 0.0022936 moles of KOH to neutralize the HBr
Molarity = moles / volume
Molarity KOH = 0.0022936 moles /0.0221 L
Molarity KOH = 0.104 M
The molarity of the potassium hydroxide solution is 0.104 M
