Answer:
6x
Step-by-step explanation:
Step 1: Write equation
x + 2x + 3x
Step 2: Combine like terms
3x + 3x
6x
Answer:
14 and 4/1000 or 14004/1000
Step-by-step explanation:
1*10+3*1+4*(1/1000)
First i like to separate the equation by PEMDAS or order of operations. First is parentheses, which is the fraction. Then is exponents. There is none. Then multiplication and division so u solve 1*10, 3*1 and 4*1/1000.
This is the updated equation: 10+4+(4/1000)
Next you do subtraction and addition. The order does not matter if there's only addition. If there is subtraction u solve by the order of the equation. SO in this step we solve 10+4+(4/1000)
Here is the updated version: 14+(4/1000)
Then u add that which is 14 and 4/1000 or you can do 14004/1000
By inspection, it's clear that the sequence must converge to

because

when

is arbitrarily large.
Now, for the limit as

to be equal to

is to say that for any

, there exists some

such that whenever

, it follows that

From this inequality, we get




As we're considering

, we can omit the first inequality.
We can then see that choosing

will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that

.
It should be 1 over 2 or 1 over 11 but im pretty sure its the first one I picked