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3 years ago

I need to earn $350,000 for a pet gorilla. In 3 days, I earn $100. How many days do I have to wait before I have $350,000

Mathematics

1 answer:

Annette [7]3 years ago

8 0

1,166 days I know this because I just did the math rig now

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Simplify the following expressions ( combine like-terms )

galina1969 [7]

Answer:

Step-by-step explanation:

Step 1: Write equation

x + 2x + 3x

Step 2: Combine like terms

3x + 3x

5 0

3 years ago

1x10+3×1+4×(1over1000)

Marina86 [1]

Answer:

14 and 4/1000 or 14004/1000

Step-by-step explanation:

1*10+3*1+4*(1/1000)

First i like to separate the equation by PEMDAS or order of operations. First is parentheses, which is the fraction. Then is exponents. There is none. Then multiplication and division so u solve 1*10, 3*1 and 4*1/1000.

This is the updated equation: 10+4+(4/1000)

Next you do subtraction and addition. The order does not matter if there's only addition. If there is subtraction u solve by the order of the equation. SO in this step we solve 10+4+(4/1000)

Here is the updated version: 14+(4/1000)

Then u add that which is 14 and 4/1000 or you can do 14004/1000

6 0

3 years ago

Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini

Nat2105 [25]

By inspection, it's clear that the sequence must converge to $\dfrac32$ because

$\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32$

when $n$ is arbitrarily large.

Now, for the limit as $n\to\infty$ to be equal to $\dfrac32$ is to say that for any $\varepsilon>0$ , there exists some $N$ such that whenever $n>N$ , it follows that

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|$

From this inequality, we get

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}$
$\implies|2n-1|>\dfrac5{2\varepsilon}$
$\implies2n-1\dfrac5{2\varepsilon}$
$\implies n\dfrac12+\dfrac5{4\varepsilon}$

As we're considering $n\to\infty$ , we can omit the first inequality.

We can then see that choosing $N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil$ will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that $N\in\mathbb N$ .

6 0

3 years ago

When converted to speeds, which list is in order from slowest to fastest?

s2008m [1.1K]

Answer:

25 =84b h +43

7 0

3 years ago

A letter is drawn at random from the word MATHEMATICS .Find the probability that the letter is vowel given that it appears only

Lapatulllka [165]

It should be 1 over 2 or 1 over 11 but im pretty sure its the first one I picked

5 0

3 years ago