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mel-nik [20]
3 years ago
13

Fluorine is a reactive nonmetal in the Halogen group. What other elements below are also likely to be reactive like fluorine?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
7 0

Answer:okay

Explanation:

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Plz help me fast plz !!!!!!
Ede4ka [16]

Answer:

I and II      I think

Explanation:

4 0
2 years ago
Read 2 more answers
What is the solubility of methylacetylene (in units of grams per liter) in water at 25 °C, when the C3H4 gas over the solution h
Luda [366]

Answer:

The solubility of methylacetylene is 0,11 g L⁻¹

Explanation:

Henry's law is a gas law that states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.

The formula is:

C = kH P

Where C is solubility of the gas (In mol/L)

kH is Henry constant (9,23x10⁻² mol L⁻¹ atm⁻¹)

An P is partial pressure (0,301 atm)

Solving, C = 2,78x10⁻³ mol L⁻¹. In grams per liter:

2,78x10⁻³ mol L⁻¹ₓ \frac{40 g}{mol} = <em>0,11 g L⁻¹</em>

<em></em>

I hope it helps!

7 0
3 years ago
How much thermal energy is added to 10.0 g of ice at −20.0°C to convert it to water vapor at 120.0°C?
Sonbull [250]

Answer:

7479 cal.

31262.2 joules

Explanation:

This is a calorimetry problem where water in its three states changes from ice to vapor.

We must use, the calorimetry formula and the formula for latent heat.

Q = m . C . ΔT

Q = Clat . m

First of all, let's determine the heat for ice, before it melts.

10 g . 0.5 cal/g°C ( 0° - (-20°C) = 100 cal

Now, the ice has melted.

Q = Clat heat of fusion . 10 g

Q = 79.7 cal/g . 10 g → 797 cal

We have water  at 0°, so this water has to receive heat until it becomes vapor. Let's determine that heat.

Q = m . C . ΔT

Q = 10 g . 1 cal/g°C (100°C - 0°C) → 1000 cal

Water is ready now, to become vapor so let's determine the heat.

Q = Clat heat of vaporization . m

Q = 539.4 cal/g . 10 g → 5394 cal

Finally we have vapor water, so let's determine the heat gained when this vapor changes the T° from 100°C to 120°

Q = m . C . ΔT

Q = 10 g . 0.470 cal/g°C . (120°C - 100°C) → 94 cal

Now, we have to sum all the heat that was added in all the process.

100 cal + 797 cal + 1000 cal + 5394 cal + 94 cal =7479 cal.

We can convert this unit to joules, which is more acceptable for energy terms.

1 cal is 4.18 Joules.

Then, 7479 cal are (7479 . 4.18) = 31262.2 joules

6 0
3 years ago
Which two structures would provide a postive idenfitacation of a plant cell under a microscope
schepotkina [342]
Chloroplast, its where photosynthesis happens and the cell wall which only plants fungi and bacteria have.
8 0
3 years ago
Read 2 more answers
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
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